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"translatedContent": "<p>给定一个方阵,其中每个单元(像素)非黑即白。设计一个算法,找出 4 条边皆为黑色像素的最大子方阵。</p>\n\n<p>返回一个数组 <code>[r, c, size]</code> ,其中 <code>r</code>, <code>c</code> 分别代表子方阵左上角的行号和列号,<code>size</code> 是子方阵的边长。若有多个满足条件的子方阵,返回 <code>r</code> 最小的,若 <code>r</code> 相同,返回 <code>c</code> 最小的子方阵。若无满足条件的子方阵,返回空数组。</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre><strong>输入:\n</strong>[\n [1,0,1],\n [<strong>0,0</strong>,1],\n [<strong>0,0</strong>,1]\n]\n<strong>输出: </strong>[1,0,2]\n<strong>解释: </strong>输入中 0 代表黑色,1 代表白色,标粗的元素即为满足条件的最大子方阵\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre><strong>输入:\n</strong>[\n [<strong>0</strong>,1,1],\n [1,0,1],\n [1,1,0]\n]\n<strong>输出: </strong>[0,0,1]\n</pre>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>matrix.length == matrix[0].length <= 200</code></li>\n</ul>\n",
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"hints": [
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"从蛮力解法开始。你能先试试最大的正方形吗?",
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"最大的正方形是N×N。所以你先试一下该正方形,如果可行,那么你便知道已经找到了最佳正方形。否则,可以尝试下一个最小的正方形。",
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