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"translatedContent": "<p>设计一个找到数据流中第 <code>k</code> 大元素的类(class)。注意是排序后的第 <code>k</code> 大元素,不是第 <code>k</code> 个不同的元素。</p>\n\n<p>请实现 <code>KthLargest</code> 类:</p>\n\n<ul>\n\t<li><code>KthLargest(int k, int[] nums)</code> 使用整数 <code>k</code> 和整数流 <code>nums</code> 初始化对象。</li>\n\t<li><code>int add(int val)</code> 将 <code>val</code> 插入数据流 <code>nums</code> 后,返回当前数据流中第 <code>k</code> 大的元素。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例:</strong></p>\n\n<pre>\n<strong>输入:</strong>\n["KthLargest", "add", "add", "add", "add", "add"]\n[[3, [4, 5, 8, 2]], [3], [5], [10], [9], [4]]\n<strong>输出:</strong>\n[null, 4, 5, 5, 8, 8]\n\n<strong>解释:</strong>\nKthLargest kthLargest = new KthLargest(3, [4, 5, 8, 2]);\nkthLargest.add(3); // return 4\nkthLargest.add(5); // return 5\nkthLargest.add(10); // return 5\nkthLargest.add(9); // return 8\nkthLargest.add(4); // return 8\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= k <= 10<sup>4</sup></code></li>\n\t<li><code>0 <= nums.length <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums[i] <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= val <= 10<sup>4</sup></code></li>\n\t<li>最多调用 <code>add</code> 方法 <code>10<sup>4</sup></code> 次</li>\n\t<li>题目数据保证,在查找第 <code>k</code> 大元素时,数组中至少有 <code>k</code> 个元素</li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 703 题相同: <a href=\"https://leetcode-cn.com/problems/kth-largest-element-in-a-stream/\">https://leetcode-cn.com/problems/kth-largest-element-in-a-stream/</a></p>\n",
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