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"translatedContent": "<p>给你一棵二叉搜索树的<meta charset=\"UTF-8\" /> <code>root</code> ,请你 <strong>按中序遍历</strong> 将其重新排列为一棵递增顺序搜索树,使树中最左边的节点成为树的根节点,并且每个节点没有左子节点,只有一个右子节点。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex1.jpg\" style=\"height: 350px; width: 600px;\" />\n<pre>\n<strong>输入:</strong>root = [5,3,6,2,4,null,8,1,null,null,null,7,9]\n<strong>输出:</strong>[1,null,2,null,3,null,4,null,5,null,6,null,7,null,8,null,9]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/17/ex2.jpg\" style=\"height: 114px; width: 300px;\" />\n<pre>\n<strong>输入:</strong>root = [5,1,7]\n<strong>输出:</strong>[1,null,5,null,7]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>树中节点数的取值范围是 <code>[1, 100]</code></li>\n\t<li><code>0 <= Node.val <= 1000</code></li>\n</ul>\n",
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