update

leetcode-cn/originData/find-valid-matrix-given-row-and-column-sums.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你两个非负整数数组 <code>rowSum</code> 和 <code>colSum</code> ，其中 <code>rowSum[i]</code> 是二维矩阵中第 <code>i</code> 行元素的和， <code>colSum[j]</code> 是第 <code>j</code> 列元素的和。换言之你不知道矩阵里的每个元素，但是你知道每一行和每一列的和。</p>\n\n<p>请找到大小为 <code>rowSum.length x colSum.length</code> 的任意 <strong>非负整数</strong> 矩阵，且该矩阵满足 <code>rowSum</code> 和 <code>colSum</code> 的要求。</p>\n\n<p>请你返回任意一个满足题目要求的二维矩阵，题目保证存在 <strong>至少一个</strong> 可行矩阵。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>rowSum = [3,8], colSum = [4,7]\n<strong>输出：</strong>[[3,0],\n      [1,7]]\n<strong>解释：</strong>\n第 0 行：3 + 0 = 3 == rowSum[0]\n第 1 行：1 + 7 = 8 == rowSum[1]\n第 0 列：3 + 1 = 4 == colSum[0]\n第 1 列：0 + 7 = 7 == colSum[1]\n行和列的和都满足题目要求，且所有矩阵元素都是非负的。\n另一个可行的矩阵为：[[1,2],\n                  [3,5]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>rowSum = [5,7,10], colSum = [8,6,8]\n<strong>输出：</strong>[[0,5,0],\n      [6,1,0],\n      [2,0,8]]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>rowSum = [14,9], colSum = [6,9,8]\n<strong>输出：</strong>[[0,9,5],\n      [6,0,3]]\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>rowSum = [1,0], colSum = [1]\n<strong>输出：</strong>[[1],\n      [0]]\n</pre>\n\n<p><strong>示例 5：</strong></p>\n\n<pre>\n<strong>输入：</strong>rowSum = [0], colSum = [0]\n<strong>输出：</strong>[[0]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= rowSum.length, colSum.length <= 500</code></li>\n\t<li><code>0 <= rowSum[i], colSum[i] <= 10<sup>8</sup></code></li>\n\t<li><code>sum(rows) == sum(columns)</code></li>\n</ul>\n",
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             "hints": [
                 "Find the smallest rowSum or colSum, and let it be x. Place that number in the grid, and subtract x from rowSum and colSum. Continue until all the sums are satisfied."
             ],