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leetcode-cn/originData/find-k-pairs-with-smallest-sums.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给定两个以 <strong>升序排列</strong> 的整数数组 <code>nums1</code> 和<strong> </strong><code>nums2</code><strong>&nbsp;</strong>,&nbsp;以及一个整数 <code>k</code><strong>&nbsp;</strong>。</p>\n\n<p>定义一对值&nbsp;<code>(u,v)</code>，其中第一个元素来自&nbsp;<code>nums1</code>，第二个元素来自 <code>nums2</code><strong>&nbsp;</strong>。</p>\n\n<p>请找到和最小的 <code>k</code>&nbsp;个数对&nbsp;<code>(u<sub>1</sub>,v<sub>1</sub>)</code>, <code>&nbsp;(u<sub>2</sub>,v<sub>2</sub>)</code> &nbsp;... &nbsp;<code>(u<sub>k</sub>,v<sub>k</sub>)</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> nums1 = [1,7,11], nums2 = [2,4,6], k = 3\n<strong>输出:</strong> [1,2],[1,4],[1,6]\n<strong>解释: </strong>返回序列中的前 3 对数：\n     [1,2],[1,4],[1,6],[7,2],[7,4],[11,2],[7,6],[11,4],[11,6]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入: </strong>nums1 = [1,1,2], nums2 = [1,2,3], k = 2\n<strong>输出: </strong>[1,1],[1,1]\n<strong>解释: </strong>返回序列中的前 2 对数：\n&nbsp;    [1,1],[1,1],[1,2],[2,1],[1,2],[2,2],[1,3],[1,3],[2,3]\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入: </strong>nums1 = [1,2], nums2 = [3], k = 3 \n<strong>输出:</strong> [1,3],[2,3]\n<strong>解释: </strong>也可能序列中所有的数对都被返回:[1,3],[2,3]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums1[i], nums2[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>nums1</code> 和 <code>nums2</code> 均为升序排列</li>\n\t<li><code>1 &lt;= k &lt;= 1000</code></li>\n</ul>\n",
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