update

leetcode-cn/originData/exchange-seats.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>表:&nbsp;<code>Seat</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type    |\n+-------------+---------+\n| id          | int     |\n| name        | varchar |\n+-------------+---------+\nId是该表的主键列。\n该表的每一行都表示学生的姓名和ID。\nId是一个连续的增量。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写SQL查询来交换每两个连续的学生的座位号。如果学生的数量是奇数，则最后一个学生的id不交换。</p>\n\n<p>按 <code>id</code> <strong>升序</strong> 返回结果表。</p>\n\n<p>查询结果格式如下所示。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nSeat 表:\n+----+---------+\n| id | student |\n+----+---------+\n| 1  | Abbot   |\n| 2  | Doris   |\n| 3  | Emerson |\n| 4  | Green   |\n| 5  | Jeames  |\n+----+---------+\n<strong>输出:</strong> \n+----+---------+\n| id | student |\n+----+---------+\n| 1  | Doris   |\n| 2  | Abbot   |\n| 3  | Green   |\n| 4  | Emerson |\n| 5  | Jeames  |\n+----+---------+\n<strong>解释:\n</strong>请注意，如果学生人数为奇数，则不需要更换最后一名学生的座位。</pre>\n",
             "isPaidOnly": false,
             "difficulty": "Medium",
-            "likes": 298,
+            "likes": 303,
             "dislikes": 0,
             "isLiked": null,
             "similarQuestions": "[]",
@@ -47,11 +47,11 @@
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             "hints": [],
             "solution": null,
             "status": null,
-            "sampleTestCase": "{\"headers\": {\"Seat\": [\"id\",\"student\"]}, \"rows\": {\"Seat\": [[1,\"Abbot\"],[2,\"Doris\"],[3,\"Emerson\"],[4,\"Green\"],[5,\"Jeames\"]]}}",
+            "sampleTestCase": "{\"headers\": {\"seat\": [\"id\",\"student\"]}, \"rows\": {\"seat\": [[1,\"Abbot\"],[2,\"Doris\"],[3,\"Emerson\"],[4,\"Green\"],[5,\"Jeames\"]]}}",
             "metaData": "{\n  \"mysql\": [\n    \"Create table If Not Exists Seat (id int, student varchar(255))\"\n  ],\n  \"mssql\": [\n    \"Create table Seat (id int, student varchar(255))\"\n  ],\n  \"oraclesql\": [\n    \"Create table Seat (id int, student varchar(255))\"\n  ],\n  \"database\": true\n}",
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