update

leetcode-cn/originData/count-special-quadruplets.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你一个 <strong>下标从 0 开始</strong> 的整数数组 <code>nums</code> ，返回满足下述条件的 <strong>不同</strong> 四元组 <code>(a, b, c, d)</code> 的 <strong>数目</strong> ：</p>\n\n<ul>\n\t<li><code>nums[a] + nums[b] + nums[c] == nums[d]</code> ，且</li>\n\t<li><code>a &lt; b &lt; c &lt; d</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,2,3,6]\n<strong>输出：</strong>1\n<strong>解释：</strong>满足要求的唯一一个四元组是 (0, 1, 2, 3) 因为 1 + 2 + 3 == 6 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>nums = [3,3,6,4,5]\n<strong>输出：</strong>0\n<strong>解释：</strong>[3,3,6,4,5] 中不存在满足要求的四元组。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>nums = [1,1,1,3,5]\n<strong>输出：</strong>4\n<strong>解释：</strong>满足要求的 4 个四元组如下：\n- (0, 1, 2, 3): 1 + 1 + 1 == 3\n- (0, 1, 3, 4): 1 + 1 + 3 == 5\n- (0, 2, 3, 4): 1 + 1 + 3 == 5\n- (1, 2, 3, 4): 1 + 1 + 3 == 5\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>4 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n</ul>\n",
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@@ -143,7 +143,7 @@
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             "hints": [
                 "N is very small, how can we use that?",
                 "Can we check every possible quadruplet?"