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小墨
2022-05-02 23:44:12 +08:00
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leetcode-cn/originData/contains-duplicate-ii.json
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@@ -12,7 +12,7 @@
"translatedContent": "<p>给你一个整数数组&nbsp;<code>nums</code> 和一个整数&nbsp;<code>k</code> ，判断数组中是否存在两个 <strong>不同的索引</strong><em>&nbsp;</em><code>i</code>&nbsp;和<em>&nbsp;</em><code>j</code> ，满足 <code>nums[i] == nums[j]</code> 且 <code>abs(i - j) &lt;= k</code> 。如果存在，返回 <code>true</code> ；否则，返回 <code>false</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,1], k<em> </em>= 3\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,0,1,1], k<em> </em>=<em> </em>1\n<strong>输出：</strong>true</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,1,2,3], k<em> </em>=<em> </em>2\n<strong>输出：</strong>false</pre>\n\n<p>&nbsp;</p>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
"isPaidOnly": false,
"difficulty": "Easy",
"likes": 462,
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"similarQuestions": "[{\"title\": \"Contains Duplicate\", \"titleSlug\": \"contains-duplicate\", \"difficulty\": \"Easy\", \"translatedTitle\": \"\\u5b58\\u5728\\u91cd\\u590d\\u5143\\u7d20\"}, {\"title\": \"Contains Duplicate III\", \"titleSlug\": \"contains-duplicate-iii\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u5b58\\u5728\\u91cd\\u590d\\u5143\\u7d20 III\"}]",
@@ -149,7 +149,7 @@
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