update

leetcode-cn/originData/combination-sum-ii.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给定一个候选人编号的集合&nbsp;<code>candidates</code>&nbsp;和一个目标数&nbsp;<code>target</code>&nbsp;，找出&nbsp;<code>candidates</code>&nbsp;中所有可以使数字和为&nbsp;<code>target</code>&nbsp;的组合。</p>\n\n<p><code>candidates</code>&nbsp;中的每个数字在每个组合中只能使用&nbsp;<strong>一次</strong>&nbsp;。</p>\n\n<p><strong>注意：</strong>解集不能包含重复的组合。&nbsp;</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1:</strong></p>\n\n<pre>\n<strong>输入:</strong> candidates =&nbsp;<code>[10,1,2,7,6,1,5]</code>, target =&nbsp;<code>8</code>,\n<strong>输出:</strong>\n[\n[1,1,6],\n[1,2,5],\n[1,7],\n[2,6]\n]</pre>\n\n<p><strong>示例&nbsp;2:</strong></p>\n\n<pre>\n<strong>输入:</strong> candidates =&nbsp;[2,5,2,1,2], target =&nbsp;5,\n<strong>输出:</strong>\n[\n[1,2,2],\n[5]\n]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;=&nbsp;candidates.length &lt;= 100</code></li>\n\t<li><code>1 &lt;=&nbsp;candidates[i] &lt;= 50</code></li>\n\t<li><code>1 &lt;= target &lt;= 30</code></li>\n</ul>\n",
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