update

leetcode-cn/originData/coin-change-2.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你一个整数数组 <code>coins</code> 表示不同面额的硬币，另给一个整数 <code>amount</code> 表示总金额。</p>\n\n<p>请你计算并返回可以凑成总金额的硬币组合数。如果任何硬币组合都无法凑出总金额，返回 <code>0</code> 。</p>\n\n<p>假设每一种面额的硬币有无限个。 </p>\n\n<p>题目数据保证结果符合 32 位带符号整数。</p>\n\n<p> </p>\n\n<ul>\n</ul>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>amount = 5, coins = [1, 2, 5]\n<strong>输出：</strong>4\n<strong>解释：</strong>有四种方式可以凑成总金额：\n5=5\n5=2+2+1\n5=2+1+1+1\n5=1+1+1+1+1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>amount = 3, coins = [2]\n<strong>输出：</strong>0\n<strong>解释：</strong>只用面额 2 的硬币不能凑成总金额 3 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>amount = 10, coins = [10] \n<strong>输出：</strong>1\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= coins.length <= 300</code></li>\n\t<li><code>1 <= coins[i] <= 5000</code></li>\n\t<li><code>coins</code> 中的所有值 <strong>互不相同</strong></li>\n\t<li><code>0 <= amount <= 5000</code></li>\n</ul>\n",
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