update

leetcode-cn/originData/check-if-two-string-arrays-are-equivalent.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给你两个字符串数组 <code>word1</code> 和 <code>word2</code> 。如果两个数组表示的字符串相同，返回<em> </em><code>true</code><em> </em>；否则，返回 <code>false</code><em> 。</em></p>\n\n<p><strong>数组表示的字符串</strong> 是由数组中的所有元素 <strong>按顺序</strong> 连接形成的字符串。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = [\"ab\", \"c\"], word2 = [\"a\", \"bc\"]\n<strong>输出：</strong>true\n<strong>解释：</strong>\nword1 表示的字符串为 \"ab\" + \"c\" -> \"abc\"\nword2 表示的字符串为 \"a\" + \"bc\" -> \"abc\"\n两个字符串相同，返回 true</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = [\"a\", \"cb\"], word2 = [\"ab\", \"c\"]\n<strong>输出：</strong>false\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1  = [\"abc\", \"d\", \"defg\"], word2 = [\"abcddefg\"]\n<strong>输出：</strong>true\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= word1.length, word2.length <= 10<sup>3</sup></code></li>\n\t<li><code>1 <= word1[i].length, word2[i].length <= 10<sup>3</sup></code></li>\n\t<li><code>1 <= sum(word1[i].length), sum(word2[i].length) <= 10<sup>3</sup></code></li>\n\t<li><code>word1[i]</code> 和 <code>word2[i]</code> 由小写字母组成</li>\n</ul>\n",
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             "difficulty": "Easy",
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@@ -143,7 +143,7 @@
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             "hints": [
                 "Concatenate all strings in the first array into a single string in the given order, the same for the second array.",
                 "Both arrays represent the same string if and only if the generated strings are the same."