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leetcode-cn/originData/broken-board-dominoes.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>你有一块棋盘，棋盘上有一些格子已经坏掉了。你还有无穷块大小为<code>1 * 2</code>的多米诺骨牌，你想把这些骨牌<strong>不重叠</strong>地覆盖在<strong>完好</strong>的格子上，请找出你最多能在棋盘上放多少块骨牌？这些骨牌可以横着或者竖着放。</p>\n\n<p>&nbsp;</p>\n\n<p>输入：<code>n, m</code>代表棋盘的大小；<code>broken</code>是一个<code>b * 2</code>的二维数组，其中每个元素代表棋盘上每一个坏掉的格子的位置。</p>\n\n<p>输出：一个整数，代表最多能在棋盘上放的骨牌数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><strong>输入：</strong>n = 2, m = 3, broken = [[1, 0], [1, 1]]\n<strong>输出：</strong>2\n<strong>解释：</strong>我们最多可以放两块骨牌：[[0, 0], [0, 1]]以及[[0, 2], [1, 2]]。（见下图）</pre>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/09/09/domino_example_1.jpg\" style=\"height: 204px; width: 304px;\"></p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 3, m = 3, broken = []\n<strong>输出：</strong>4\n<strong>解释：</strong>下图是其中一种可行的摆放方式\n</pre>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2019/09/09/domino_example_2.jpg\" style=\"height: 304px; width: 304px;\"></p>\n\n<p>&nbsp;</p>\n\n<p><strong>限制：</strong></p>\n\n<ol>\n\t<li><code>1 &lt;= n &lt;= 8</code></li>\n\t<li><code>1 &lt;= m &lt;= 8</code></li>\n\t<li><code>0 &lt;= b &lt;= n * m</code></li>\n</ol>\n",
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