update

leetcode-cn/originData/airplane-seat-assignment-probability.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>有 <code>n</code> 位乘客即将登机，飞机正好有 <code>n</code> 个座位。第一位乘客的票丢了，他随便选了一个座位坐下。</p>\n\n<p>剩下的乘客将会：</p>\n\n<ul>\n\t<li>\n\t<p>如果他们自己的座位还空着，就坐到自己的座位上，</p>\n\t</li>\n\t<li>当他们自己的座位被占用时，随机选择其他座位</li>\n</ul>\n\n<p>第 <code>n</code>&nbsp;位乘客坐在自己的座位上的概率是多少？</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1\n<strong>输出：</strong>1.00000\n<strong>解释：</strong>第一个人只会坐在自己的位置上。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入:</strong> n = 2\n<strong>输出:</strong> 0.50000\n<strong>解释：</strong>在第一个人选好座位坐下后，第二个人坐在自己的座位上的概率是 0.5。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10^5</code></li>\n</ul>\n",
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             "difficulty": "Medium",
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@@ -155,7 +155,7 @@
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             "hints": [
                 "Let f(n) denote the probability of the n-th person getting correct seat in n-person case, then:\r\n\r\nf(1) = 1 (base case, trivial)\r\nf(2) = 1/2 (also trivial)",
                 "Try to calculate f(3), f(4), and f(5) using the base cases. What if the value of them?\r\nf(i) for i >= 2 will also be 1/2.",