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"translatedContent": "<p>给定一个二叉树的根节点 <code>root</code> ,和一个整数 <code>targetSum</code> ,求该二叉树里节点值之和等于 <code>targetSum</code> 的 <strong>路径</strong> 的数目。</p>\n\n<p><strong>路径</strong> 不需要从根节点开始,也不需要在叶子节点结束,但是路径方向必须是向下的(只能从父节点到子节点)。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg\" style=\"width: 452px; \" /></p>\n\n<pre>\n<strong>输入:</strong>root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8\n<strong>输出:</strong>3\n<strong>解释:</strong>和等于 8 的路径有 3 条,如图所示。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22\n<strong>输出:</strong>3\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>二叉树的节点个数的范围是 <code>[0,1000]</code></li>\n\t<li><meta charset=\"UTF-8\" /><code>-10<sup><span style=\"font-size: 9.449999809265137px;\">9</span></sup> <= Node.val <= 10<sup><span style=\"font-size: 9.449999809265137px;\">9</span></sup></code> </li>\n\t<li><code>-1000 <= targetSum <= 1000</code> </li>\n</ul>\n\n<p> </p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 437 题相同:<a href=\"https://leetcode-cn.com/problems/path-sum-iii/\">https://leetcode-cn.com/problems/path-sum-iii/</a></p>\n",
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