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leetcode-cn/originData/01-matrix.json

@@ -12,7 +12,7 @@
             "translatedContent": "<p>给定一个由 <code>0</code> 和 <code>1</code> 组成的矩阵 <code>mat</code> ，请输出一个大小相同的矩阵，其中每一个格子是 <code>mat</code> 中对应位置元素到最近的 <code>0</code> 的距离。</p>\n\n<p>两个相邻元素间的距离为 <code>1</code> 。</p>\n\n<p> </p>\n\n<p><b>示例 1：</b></p>\n\n<p><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626667201-NCWmuP-image.png\" style=\"width: 150px; \" /></p>\n\n<pre>\n<strong>输入：</strong>mat =<strong> </strong>[[0,0,0],[0,1,0],[0,0,0]]\n<strong>输出：</strong>[[0,0,0],[0,1,0],[0,0,0]]\n</pre>\n\n<p><b>示例 2：</b></p>\n\n<p><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626667205-xFxIeK-image.png\" style=\"width: 150px; \" /></p>\n\n<pre>\n<b>输入：</b>mat =<b> </b>[[0,0,0],[0,1,0],[1,1,1]]\n<strong>输出：</strong>[[0,0,0],[0,1,0],[1,2,1]]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == mat.length</code></li>\n\t<li><code>n == mat[i].length</code></li>\n\t<li><code>1 <= m, n <= 10<sup>4</sup></code></li>\n\t<li><code>1 <= m * n <= 10<sup>4</sup></code></li>\n\t<li><code>mat[i][j] is either 0 or 1.</code></li>\n\t<li><code>mat</code> 中至少有一个 <code>0 </code></li>\n</ul>\n",
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