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算法题/partition-array-for-maximum-sum.html

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+<p>Given an integer array <code>arr</code>, partition the array into (contiguous) subarrays of length <strong>at most</strong> <code>k</code>. After partitioning, each subarray has their values changed to become the maximum value of that subarray.</p>
+
+<p>Return <em>the largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a <strong>32-bit</strong> integer.</em></p>
+
+<p>&nbsp;</p>
+<p><strong>Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> arr = [1,15,7,9,2,5,10], k = 3
+<strong>Output:</strong> 84
+<strong>Explanation:</strong> arr becomes [15,15,15,9,10,10,10]
+</pre>
+
+<p><strong>Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> arr = [1,4,1,5,7,3,6,1,9,9,3], k = 4
+<strong>Output:</strong> 83
+</pre>
+
+<p><strong>Example 3:</strong></p>
+
+<pre>
+<strong>Input:</strong> arr = [1], k = 1
+<strong>Output:</strong> 1
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= arr.length &lt;= 500</code></li>
+	<li><code>0 &lt;= arr[i] &lt;= 10<sup>9</sup></code></li>
+	<li><code>1 &lt;= k &lt;= arr.length</code></li>
+</ul>