coder-xiaomo/leetcode-problemset
1
0
Fork 0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-10-12 17:05:15 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee

update

Browse Source
This commit is contained in:
小墨
2025-09-29 14:43:44 +08:00
parent 2862a227c4
commit 13f2098086
4409 changed files with 168933 additions and 166256 deletions
Download Patch File Download Diff File Expand all files Collapse all files

4
leetcode-cn/problem (English)/合法分割的最小下标(English) [minimum-index-of-a-valid-split].html
View File

@@ -1,6 +1,6 @@
<p>An element <code>x</code> of an integer array <code>arr</code> of length <code>m</code> is <strong>dominant</strong> if <code>freq(x) * 2 &gt; m</code>, where <code>freq(x)</code> is the number of occurrences of <code>x</code> in <code>arr</code>. Note that this definition implies that <code>arr</code> can have <strong>at most one</strong> dominant element.</p>
<p>An element <code>x</code> of an integer array <code>arr</code> of length <code>m</code> is <strong>dominant</strong> if <strong>more than half</strong> the elements of <code>arr</code> have a value of <code>x</code>.</p>
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code> with one dominant element.</p>
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code> with one <strong>dominant</strong> element.</p>
<p>You can split <code>nums</code> at an index <code>i</code> into two arrays <code>nums[0, ..., i]</code> and <code>nums[i + 1, ..., n - 1]</code>, but the split is only <strong>valid</strong> if:</p>