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2025-09-29 14:43:44 +08:00
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leetcode-cn/originData/promise-time-limit.json
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@@ -12,12 +12,12 @@
"translatedContent": "<p>请你编写一个函数，它接受一个异步函数 <code>fn</code>&nbsp;和一个以毫秒为单位的时间 <code>t</code>。它应根据限时函数返回一个有 <strong>限时</strong> 效果的函数。函数 <code>fn</code> 接受提供给 <strong>限时</strong> 函数的参数。</p>\n\n<p><strong>限时</strong> 函数应遵循以下规则：</p>\n\n<ul>\n\t<li>如果 <code>fn</code> 在 <code>t</code> 毫秒的时间限制内完成，<strong>限时</strong> 函数应返回结果。</li>\n\t<li>如果 <code>fn</code> 的执行超过时间限制，<strong>限时&nbsp;</strong>函数应拒绝并返回字符串 <code>\"Time Limit Exceeded\"</code> 。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><b>示例 1：</b></p>\n\n<pre>\n<strong>输入：</strong>\nfn = async (n) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 100)); \n&nbsp; return n * n; \n}\ninputs = [5]\nt = 50\n<strong>输出：</strong>{\"rejected\":\"Time Limit Exceeded\",\"time\":50}\n<strong>解释：</strong>\nconst limited = timeLimit(fn, t)\nconst start = performance.now()\nlet result;\ntry {\n&nbsp; &nbsp;const res = await limited(...inputs)\n&nbsp; &nbsp;result = {\"resolved\": res, \"time\": Math.floor(performance.now() - start)};\n} catch (err) {\n&nbsp; result = {\"rejected\": err, \"time\": Math.floor(performance.now() - start)};\n}\nconsole.log(result) // 输出结果\n<b>\n</b>提供的函数设置在 100ms 后执行完成，但是设置的超时时间为 50ms，所以在 t=50ms 时拒绝因为达到了超时时间。\n</pre>\n\n<p><b>示例 2：</b></p>\n\n<pre>\n<strong>输入：</strong>\nfn = async (n) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 100)); \n&nbsp; return n * n; \n}\ninputs = [5]\nt = 150\n<strong>输出：</strong>{\"resolved\":25,\"time\":100}\n<strong>解释：</strong>\n在 t=100ms 时执行 5*5=25 ，没有达到超时时间。\n</pre>\n\n<p><b>示例 3：</b></p>\n\n<pre>\n<strong>输入：</strong>\nfn = async (a, b) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 120)); \n&nbsp; return a + b; \n}\ninputs = [5,10]\nt = 150\n<strong>输出：</strong>{\"resolved\":15,\"time\":120}\n<strong>解释：</strong><b>\n</b>在 t=120ms 时执行 5+10=15，没有达到超时时间。\n</pre>\n\n<p><b>示例 4：</b></p>\n\n<pre>\n<strong>输入：</strong>\nfn = async () =&gt; { \n&nbsp; throw \"Error\";\n}\ninputs = []\nt = 1000\n<strong>输出：</strong>{\"rejected\":\"Error\",\"time\":0}\n<strong>解释：</strong>\n此函数始终丢出 Error</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>0 &lt;= inputs.length &lt;= 10</code></li>\n\t<li><code>0 &lt;= t &lt;= 1000</code></li>\n\t<li><code>fn</code> 返回一个 Promise 对象</li>\n</ul>\n",
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@@ -34,7 +34,7 @@
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"hints": [
"You can return a copy of a function with: \r\n\r\nfunction outerFunction(fn) { \r\n return function innerFunction(...params) {\r\n return fn(...params);\r\n };\r\n}",
"Inside the inner function, you will need to return a new Promise.",
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