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leetcode-cn/originData/interval-cancellation.json
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@@ -12,12 +12,12 @@
"translatedContent": "<p>现给定一个函数 <code>fn</code>，一个参数数组 <code>args</code> 和一个时间间隔 <code>t</code>，返回一个取消函数 <code>cancelFn</code>。</p>\n\n<p>在经过 <code>cancelTimeMs</code> 毫秒的延迟后，将调用返回的取消函数 <code>cancelFn</code>。</p>\n\n<pre>\nsetTimeout(cancelFn, cancelTimeMs)\n</pre>\n\n<p>函数 <code>fn</code> 应立即使用参数 <code>args</code> 调用，然后每隔 <code>t</code> 毫秒调用一次，直到在 <code>cancelTimeMs</code> 毫秒时调用 <code>cancelFn</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x) =&gt; x * 2, args = [4], t = 35, cancelT = 190\n<b>输出：</b>\n[\n {\"time\": 0, \"returned\": 8},\n {\"time\": 35, \"returned\": 8},\n {\"time\": 70, \"returned\": 8},\n {\"time\": 105, \"returned\": 8},\n {\"time\": 140, \"returned\": 8},\n {\"time\": 175, \"returned\": 8}\n]\n<strong>解释：</strong> \nconst cancelTimeMs = 190;\nconst cancelFn = cancellable((x) =&gt; x * 2, [4], 35);\nsetTimeout(cancelFn, cancelTimeMs);\n\n每隔 35ms，调用 fn(4)。直到 t=190ms，然后取消。\n第一次调用 fn 是在 0ms。fn(4) 返回 8。\n第二次调用 fn 是在 35ms。fn(4) 返回 8。\n第三次调用 fn 是在 70ms。fn(4) 返回 8。\n第四次调用 fn 是在&nbsp;105ms。fn(4) 返回 8。\n第五次调用 fn 是在 140ms。fn(4) 返回 8。\n第六次调用 fn 是在 175ms。fn(4) 返回 8。\n在 t=190ms 时取消\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x1, x2) =&gt; (x1 * x2), args = [2, 5], t = 30, cancelT = 165\n<strong>输出：</strong> \n[\n {\"time\": 0, \"returned\": 10},\n {\"time\": 30, \"returned\": 10},\n {\"time\": 60, \"returned\": 10},\n {\"time\": 90, \"returned\": 10},\n {\"time\": 120, \"returned\": 10},\n {\"time\": 150, \"returned\": 10}\n]\n<strong>解释：</strong>\nconst cancelTimeMs = 165; \nconst cancelFn = cancellable((x1, x2) =&gt; (x1 * x2), [2, 5], 30) \nsetTimeout(cancelFn, cancelTimeMs)\n\n每隔 30ms，调用 fn(2, 5)。直到 t=165ms，然后取消。\n第一次调用 fn 是在 0ms\n第二次调用 fn 是在 30ms\n第三次调用 fn 是在 60ms\n第四次调用 fn 是在&nbsp;90ms\n第五次调用 fn 是在 120ms\n第六次调用 fn 是在 150ms\n在 165ms 取消\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>fn = (x1, x2, x3) =&gt; (x1 + x2 + x3), args = [5, 1, 3], t = 50, cancelT = 180\n<b>输出：</b>\n[\n {\"time\": 0, \"returned\": 9},\n {\"time\": 50, \"returned\": 9},\n {\"time\": 100, \"returned\": 9},\n {\"time\": 150, \"returned\": 9}\n]\n<b>解释：</b>\nconst cancelTimeMs = 180;\nconst cancelFn = cancellable((x1, x2, x3) =&gt; (x1 + x2 + x3), [5, 1, 3], 50)\nsetTimeout(cancelFn, cancelTimeMs)\n\n每隔 50ms，调用 fn(5, 1, 3)。直到 t=180ms，然后取消。\n第一次调用 fn 是在 0ms\n第二次调用 fn 是在 50ms\n第三次调用 fn 是在 100ms\n第四次调用 fn 是在&nbsp;150ms\n在 180ms 取消\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>fn</code> 是一个函数</li>\n\t<li><code>args</code> 是一个有效的 JSON 数组</li>\n\t<li><code>1 &lt;= args.length &lt;= 10</code></li>\n\t<li><code><font face=\"monospace\">30 &lt;= t &lt;= 100</font></code></li>\n\t<li><code><font face=\"monospace\">10 &lt;= cancelT &lt;= 500</font></code></li>\n</ul>\n",
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