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mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-10-22 05:26:46 +08:00
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2025-09-29 14:43:44 +08:00
parent 2862a227c4
commit 13f2098086
4409 changed files with 168933 additions and 166256 deletions

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@@ -12,12 +12,12 @@
"translatedContent": "<p>表:<code>Employee</code>&nbsp;</p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| id | int |\n| name | varchar |\n| salary | int |\n| managerId | int |\n+-------------+---------+\nid 是该表的主键(具有唯一值的列)。\n该表的每一行都表示雇员的ID、姓名、工资和经理的ID。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>编写解决方案,找出收入比经理高的员工。</p>\n\n<p>以 <strong>任意顺序</strong> 返回结果表。</p>\n\n<p>结果格式如下所示。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong> \nEmployee 表:\n+----+-------+--------+-----------+\n| id | name | salary | managerId |\n+----+-------+--------+-----------+\n| 1 | Joe | 70000 | 3 |\n| 2 | Henry | 80000 | 4 |\n| 3 | Sam | 60000 | Null |\n| 4 | Max | 90000 | Null |\n+----+-------+--------+-----------+\n<strong>输出:</strong> \n+----------+\n| Employee |\n+----------+\n| Joe |\n+----------+\n<strong>解释:</strong> Joe 是唯一挣得比经理多的雇员。</pre>\n",
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"difficulty": "Easy",
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@@ -40,6 +40,12 @@
"code": "/* Write your T-SQL query statement below */",
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@@ -51,15 +57,9 @@
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"code": "import pandas as pd\n\ndef find_employees(employee: pd.DataFrame) -> pd.DataFrame:\n ",
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