mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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"translatedContent": "<p>编写一个函数,这个函数接收一个整数数组 <code>arr</code> 和一个映射函数 <code>fn</code> ,通过该映射函数返回一个新的数组。</p>\n\n<p>返回数组的创建语句应为 <code>returnedArray[i] = fn(arr[i], i)</code> 。</p>\n\n<p>请你在不使用内置方法 <code>Array.map</code> 的前提下解决这个问题。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>arr = [1,2,3], fn = function plusone(n) { return n + 1; }\n<strong>输出:</strong>[2,3,4]\n<strong>解释: </strong>\nconst newArray = map(arr, plusone); // [2,3,4]\n此映射函数返回值是将数组中每个元素的值加 1。\n</pre>\n\n<p><strong class=\"example\">示例</strong><strong class=\"example\"> 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>arr = [1,2,3], fn = function plusI(n, i) { return n + i; }\n<strong>输出:</strong>[1,3,5]\n<strong>解释:</strong>此映射函数返回值根据输入数组索引增加每个值。\n</pre>\n\n<p><strong class=\"example\">示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>arr = [10,20,30], fn = function constant() { return 42; }\n<strong>输出:</strong>[42,42,42]\n<strong>解释:</strong>此映射函数返回值恒为 42。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>0 <= arr.length <= 1000</code></li>\n\t<li><code><font face=\"monospace\">-10<sup>9</sup> <= arr[i] <= 10<sup>9</sup></font></code></li>\n\t<li><font face=\"monospace\"><code>fn</code> 返回一个整数。</font></li>\n</ul>\n<span style=\"display:block\"><span style=\"height:0px\"><span style=\"position:absolute\"></span></span></span>",
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"Start by creating an array that will eventually be returned.",
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"Loop over each element in the passed array. Push fn(arr[i]) to the returned array."
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