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add leetcode problem-cn part2

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<p>给定两个整型数字 <code>N</code><code>M</code>,以及表示比特位置的 <code>i</code><code>j</code><code>i <= j</code>,且从 0 位开始计算)。</p>
<p>编写一种方法,使 <code>M</code> 对应的二进制数字插入 <code>N</code> 对应的二进制数字的第 <code>i ~ j</code> 位区域,不足之处用 <code>0</code> 补齐。具体插入过程如图所示。</p>
<p><img alt="" src="https://pic.leetcode-cn.com/1610104070-NuLVQi-05.01.gif" style="width: 267px; height: 200px;" /></p>
<p>题目保证从 <code>i</code> 位到 <code>j</code> 位足以容纳 <code>M</code> 例如: <code>M = 10011</code>,则 <code>ij</code> 区域至少可容纳 5 位。</p>
<p> </p>
<p><strong>示例1:</strong></p>
<pre>
<strong> 输入</strong>N = 1024(10000000000), M = 19(10011), i = 2, j = 6
<strong> 输出</strong>N = 1100(10001001100)
</pre>
<p><strong>示例2:</strong></p>
<pre>
<strong> 输入</strong> N = 0, M = 31(11111), i = 0, j = 4
<strong> 输出</strong>N = 31(11111)
</pre>