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add leetcode problem-cn part2
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算法题(国内版)/problem (Chinese)/多次搜索 [multi-search-lcci].html
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算法题(国内版)/problem (Chinese)/多次搜索 [multi-search-lcci].html
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<p>给定一个较长字符串<code>big</code>和一个包含较短字符串的数组<code>smalls</code>,设计一个方法,根据<code>smalls</code>中的每一个较短字符串,对<code>big</code>进行搜索。输出<code>smalls</code>中的字符串在<code>big</code>里出现的所有位置<code>positions</code>,其中<code>positions[i]</code>为<code>smalls[i]</code>出现的所有位置。</p>
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<p><strong>示例:</strong></p>
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<pre><strong>输入:</strong>
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big = "mississippi"
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smalls = ["is","ppi","hi","sis","i","ssippi"]
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<strong>输出:</strong> [[1,4],[8],[],[3],[1,4,7,10],[5]]
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</pre>
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<p><strong>提示:</strong></p>
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<ul>
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<li><code>0 <= len(big) <= 1000</code></li>
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<li><code>0 <= len(smalls[i]) <= 1000</code></li>
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<li><code>smalls</code>的总字符数不会超过 100000。</li>
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<li>你可以认为<code>smalls</code>中没有重复字符串。</li>
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<li>所有出现的字符均为英文小写字母。</li>
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</ul>
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