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add leetcode problem-cn part6

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<p>表:&nbsp;<code>Person</code></p>
<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| email | varchar |
+-------------+---------+
id是该表的主键列。
该表的每一行包含一封电子邮件。电子邮件将不包含大写字母。
</pre>
<p>&nbsp;</p>
<p>编写一个SQL查询来 <strong>删除</strong> 所有重复的电子邮件只保留一个id最小的唯一电子邮件。</p>
<p><strong>任意顺序</strong> 返回结果表。</p>
<p>查询结果格式如下所示。</p>
<p>&nbsp;</p>
<p><strong>示例 1:</strong></p>
<pre>
<strong>输入:</strong>
Person 表:
+----+------------------+
| id | email |
+----+------------------+
| 1 | john@example.com |
| 2 | bob@example.com |
| 3 | john@example.com |
+----+------------------+
<strong>输出:</strong>
+----+------------------+
| id | email |
+----+------------------+
| 1 | john@example.com |
| 2 | bob@example.com |
+----+------------------+
<strong>解释:</strong> john@example.com重复两次。我们保留最小的Id = 1。</pre>