mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 19:18:14 +08:00
66 lines
2.0 KiB
HTML
66 lines
2.0 KiB
HTML
|
<p>给你两个非负整数数组 <code>rowSum</code> 和 <code>colSum</code> ，其中 <code>rowSum[i]</code> 是二维矩阵中第 <code>i</code> 行元素的和， <code>colSum[j]</code> 是第 <code>j</code> 列元素的和。换言之你不知道矩阵里的每个元素，但是你知道每一行和每一列的和。</p>
|
|||
|
|
|
|||
|
|
<p>请找到大小为 <code>rowSum.length x colSum.length</code> 的任意 <strong>非负整数</strong> 矩阵，且该矩阵满足 <code>rowSum</code> 和 <code>colSum</code> 的要求。</p>
|
|||
|
|
|
|||
|
|
<p>请你返回任意一个满足题目要求的二维矩阵，题目保证存在 <strong>至少一个</strong> 可行矩阵。</p>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>示例 1：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>rowSum = [3,8], colSum = [4,7]
|
|||
|
|
<strong>输出：</strong>[[3,0],
|
|||
|
|
[1,7]]
|
|||
|
|
<strong>解释：</strong>
|
|||
|
|
第 0 行：3 + 0 = 3 == rowSum[0]
|
|||
|
|
第 1 行：1 + 7 = 8 == rowSum[1]
|
|||
|
|
第 0 列：3 + 1 = 4 == colSum[0]
|
|||
|
|
第 1 列：0 + 7 = 7 == colSum[1]
|
|||
|
|
行和列的和都满足题目要求，且所有矩阵元素都是非负的。
|
|||
|
|
另一个可行的矩阵为：[[1,2],
|
|||
|
|
[3,5]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 2：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>rowSum = [5,7,10], colSum = [8,6,8]
|
|||
|
|
<strong>输出：</strong>[[0,5,0],
|
|||
|
|
[6,1,0],
|
|||
|
|
[2,0,8]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 3：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>rowSum = [14,9], colSum = [6,9,8]
|
|||
|
|
<strong>输出：</strong>[[0,9,5],
|
|||
|
|
[6,0,3]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 4：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>rowSum = [1,0], colSum = [1]
|
|||
|
|
<strong>输出：</strong>[[1],
|
|||
|
|
[0]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 5：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>rowSum = [0], colSum = [0]
|
|||
|
|
<strong>输出：</strong>[[0]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>提示：</strong></p>
|
|||
|
|
|
|||
|
|
<ul>
|
|||
|
|
<li><code>1 <= rowSum.length, colSum.length <= 500</code></li>
|
|||
|
|
<li><code>0 <= rowSum[i], colSum[i] <= 10<sup>8</sup></code></li>
|
|||
|
|
<li><code>sum(rows) == sum(columns)</code></li>
|
|||
|
|
</ul>
|