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39 lines
1.4 KiB
HTML
39 lines
1.4 KiB
HTML
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<p>给定平面上<em> </em><code>n</code><em> </em>对 <strong>互不相同</strong> 的点 <code>points</code> ，其中 <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 。<strong>回旋镖</strong> 是由点 <code>(i, j, k)</code> 表示的元组 ，其中 <code>i</code> 和 <code>j</code> 之间的距离和 <code>i</code> 和 <code>k</code> 之间的欧式距离相等（<strong>需要考虑元组的顺序</strong>）。</p>
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<p>返回平面上所有回旋镖的数量。</p>
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<p><strong>示例 1：</strong></p>
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<pre>
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<strong>输入：</strong>points = [[0,0],[1,0],[2,0]]
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<strong>输出：</strong>2
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<strong>解释：</strong>两个回旋镖为 <strong>[[1,0],[0,0],[2,0]]</strong> 和 <strong>[[1,0],[2,0],[0,0]]</strong>
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</pre>
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<p><strong>示例 2：</strong></p>
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<pre>
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<strong>输入：</strong>points = [[1,1],[2,2],[3,3]]
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<strong>输出：</strong>2
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</pre>
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<p><strong>示例 3：</strong></p>
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<pre>
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<strong>输入：</strong>points = [[1,1]]
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<strong>输出：</strong>0
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>n == points.length</code></li>
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<li><code>1 <= n <= 500</code></li>
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<li><code>points[i].length == 2</code></li>
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<li><code>-10<sup>4</sup> <= x<sub>i</sub>, y<sub>i</sub> <= 10<sup>4</sup></code></li>
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<li>所有点都 <strong>互不相同</strong></li>
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</ul>
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