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< p > Table: < code > Employees< / code > < / p >
< pre >
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| employee_id | int |
| name | varchar |
| salary | int |
+-------------+---------+
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employee_id is the primary key (column with unique values) for this table.
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Each row of this table indicates the employee ID, employee name, and salary.
< / pre >
< p > < / p >
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< p > Write a solution to calculate the bonus of each employee. The bonus of an employee is < code > 100%< / code > of their salary if the ID of the employee is < strong > an odd number< / strong > and < strong > the employee' s name does not start with the character < / strong > < code > ' M' < / code > . The bonus of an employee is < code > 0< / code > otherwise.< / p >
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< p > Return the result table ordered by < code > employee_id< / code > .< / p >
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< p > The result format is in the following example.< / p >
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< p > < / p >
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< p > < strong class = "example" > Example 1:< / strong > < / p >
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< pre >
< strong > Input:< / strong >
Employees table:
+-------------+---------+--------+
| employee_id | name | salary |
+-------------+---------+--------+
| 2 | Meir | 3000 |
| 3 | Michael | 3800 |
| 7 | Addilyn | 7400 |
| 8 | Juan | 6100 |
| 9 | Kannon | 7700 |
+-------------+---------+--------+
< strong > Output:< / strong >
+-------------+-------+
| employee_id | bonus |
+-------------+-------+
| 2 | 0 |
| 3 | 0 |
| 7 | 7400 |
| 8 | 0 |
| 9 | 7700 |
+-------------+-------+
< strong > Explanation:< / strong >
The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id.
The employee with ID 3 gets 0 bonus because their name starts with ' M' .
The rest of the employees get a 100% bonus.
< / pre >