"content":"<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code>.</p>\n\n<p>We want to group the indices so for each index <code>i</code> in the range <code>[0, n - 1]</code>, it is assigned to <strong>exactly one</strong> group.</p>\n\n<p>A group<strong> </strong>assignment is <strong>valid</strong> if the following conditions hold:</p>\n\n<ul>\n\t<li>For every group <code>g</code>, all indices <code>i</code> assigned to group <code>g</code> have the same value in <code>nums</code>.</li>\n\t<li>For any two groups <code>g<sub>1</sub></code> and <code>g<sub>2</sub></code>, the <strong>difference</strong> between the <strong>number of indices</strong> assigned to <code>g<sub>1</sub></code> and <code>g<sub>2</sub></code> should <strong>not exceed</strong> <code>1</code>.</li>\n</ul>\n\n<p>Return <em>an integer denoting </em><em>the <strong>minimum</strong> number of groups needed to create a valid group assignment.</em></p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,2,3,2,3]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> One way the indices can be assigned to 2 groups is as follows, where the values in square brackets are indices:\ngroup 1 -> [0,2,4]\ngroup 2 -> [1,3]\nAll indices are assigned to one group.\nIn group 1, nums[0] == nums[2] == nums[4], so all indices have the same value.\nIn group 2, nums[1] == nums[3], so all indices have the same value.\nThe number of indices assigned to group 1 is 3, and the number of indices assigned to group 2 is 2.\nTheir difference doesn't exceed 1.\nIt is not possible to use fewer than 2 groups because, in order to use just 1 group, all indices assigned to that group must have the same value.\nHence, the answer is 2.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,10,10,3,1,1]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> One way the indices can be assigned to 4 groups is as follows, where the values in square brackets are indices:\ngroup 1 -> [0]\ngroup 2 -> [1,2]\ngroup 3 -> [3]\ngroup 4 -> [4,5]\nThe group assignment above satisfies both conditions.\nIt can be shown that it is not possible to create a valid assignment using fewer than 4 groups.\nHence, the answer is 4.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
"For each <code>x</code> in the range <code>[1, minimum_frequency]</code>, try to create groups with either <code>x</code> or <code>x + 1</code> indices assigned to them while minimizing the total number of groups.",
"For each distinct number, using its frequency, check that all its occurrences can be assigned to groups of size <code>x</code> or <code>x + 1</code> while minimizing the number of groups used.",
"To get the minimum number of groups needed for a number having frequency <code>f</code> to be assigned to groups of size <code>x</code> or <code>x + 1</code>, let <code>a = f / (x + 1)</code> and <code>b = f % (x + 1)</code>. <ul> <li>If <code>b == 0</code>, then we can simply create <code>a</code> groups of size <code>x + 1</code>.</li> <li>If <code>x - b <= a</code>, we can have <code>a - (x - b)</code> groups of size <code>x + 1</code> and <code>x - b + 1</code> groups of size <code>x</code>. So, in total, we have <code>a + 1</code> groups.</li> <li>Otherwise, it's impossible.</li> </ul>",
"The minimum number of groups needed for some <code>x</code> is the total minimized number of groups needed for each distinct number.",
"The answer is the minimum number of groups needed for each <code>x</code> in the range <code>[1, minimum_frequency]</code>."
"envInfo":"{\"cpp\": [\"C++\", \"<p>Compiled with <code> clang 11 </code> using the latest C++ 20 standard.</p>\\r\\n\\r\\n<p>Your code is compiled with level two optimization (<code>-O2</code>). <a href=\\\"https://github.com/google/sanitizers/wiki/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer</a> is also enabled to help detect out-of-bounds and use-after-free bugs.</p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\"], \"java\": [\"Java\", \"<p><code>OpenJDK 17</code>. Java 8 features such as lambda expressions and stream API can be used. </p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\\r\\n<p>Includes <code>Pair</code> class from https://docs.oracle.com/javase/8/javafx/api/javafx/util/Pair.html.</p>\"], \"python\": [\"Python\", \"<p><code>Python 2.7.12</code>.</p>\\r\\n\\r\\n<p>Most libraries are already imported automatically for your convenience, such as <a href=\\\"https://docs.python.org/2/library/array.html\\\" target=\\\"_blank\\\">array</a>, <a href=\\\"https://docs.python.org/2/library/bisect.html\\\" target=\\\"_blank\\\">bisect</a>, <a href=\\\"https://docs.python.org/2/library/collections.html\\\" target=\\\"_blank\\\">collections</a>. If you need more libraries, you can import it yourself.</p>\\r\\n\\r\\n<p>For Map/TreeMap data structure, you may use <a href=\\\"http://www.grantjenks.com/docs/sortedcontainers/\\\" target=\\\"_blank\\\">sortedcontainers</a> library.</p>\\r\\n\\r\\n<p>Note that Python 2.7 <a href=\\\"https://www.python.org/dev/peps/pep-0373/\\\" target=\\\"_blank\\\">will not be maintained past 2020</a>. For the latest Python, please choose Python3 instead.</p>\"], \"c\": [\"C\", \"<p>Compiled with <code>gcc 8.2</code> using the gnu11 standard.</p>\\r\\n\\r\\n<p>Your code is compiled with level one optimization (<code>-O1</code>). <a href=\\\"https://github.com/google/sanitizers/wiki/AddressSanitizer\\\" target=\\\"_blank\\\">AddressSanitizer</a> is also enabled to help detect out-of-bounds and use-after-free bugs.</p>\\r\\n\\r\\n<p>Most standard library headers are already included automatically for your convenience.</p>\\r\\n\\r\\n<p>For hash table operations, you may use <a href=\\\"https://troydhanson.github.io/uthash/\\\" target=\\\"_blank\\\">uthash</a>. \\\"uthash.h\\\" is included by default. Below are some examples:</p>\\r\\n\\r\\n<p><b>1. Adding an item to a hash.</b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n int id; /* we'll use this field as the key */\\r\\n char name[10];\\r\\n UT_hash_handle hh; /* makes this structure hashable */\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>2. Looking up an item in a hash:</b>\\r\\n<pre>\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n</pre>\\r\\n</p>\\r\\n\\r\\n<p><b>3. Deleting an item in a hash:</b>\\r\\n<pre>\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n</pre>\\r\\n</p>\"], \"csharp\": [\"C#\", \"<p><a href=\\\"https://learn.microsoft.com/en-us/dotnet/csharp/whats-new/csharp-10\\\" target=\\\"_blank\\\">C# 10 with .NET 6 runtime</a></p>\"], \"javascript\": [\"JavaScript\", \"<p><code>Node.js 16.13.2</code>.</p>\\r\\n\\r\\n<p>Your code is run with <code>--harmony</code> flag, enabling <a href=\\\"http://node.green/\\\" target=\\\"_blank\\\">new ES6 features</a>.</p>\\r\\n\\r\\n<p><a href=\\\"https://lodash.com\\\" target=\\\"_blank\\\">lodash.js</a> library is included by default.</p>\\r\\n\\r\\n<p>For Priority Queue / Queue data structures, you may use 5.3.0 version of <a href=\\\"https://github.com/datastructures-js/priority-queue/tree/fb4fdb984834421279aeb081df7af624d17c2a03\\\" target=\\\"_blank\\\">datastructures-js/priority-queue</a> and 4.2.1 version of <a href=\\\"https://githu
