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leetcode-problemset/leetcode/originData/find-the-longest-equal-subarray.json

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{
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"title": "Find the Longest Equal Subarray",
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"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>k</code>.</p>\n\n<p>A subarray is called <strong>equal</strong> if all of its elements are equal. Note that the empty subarray is an <strong>equal</strong> subarray.</p>\n\n<p>Return <em>the length of the <strong>longest</strong> possible equal subarray after deleting <strong>at most</strong> </em><code>k</code><em> elements from </em><code>nums</code>.</p>\n\n<p>A <b>subarray</b> is a contiguous, possibly empty sequence of elements within an array.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,2,3,1,3], k = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> It&#39;s optimal to delete the elements at index 2 and index 4.\nAfter deleting them, nums becomes equal to [1, 3, 3, 3].\nThe longest equal subarray starts at i = 1 and ends at j = 3 with length equal to 3.\nIt can be proven that no longer equal subarrays can be created.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,1,2,2,1,1], k = 2\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> It&#39;s optimal to delete the elements at index 2 and index 3.\nAfter deleting them, nums becomes equal to [1, 1, 1, 1].\nThe array itself is an equal subarray, so the answer is 4.\nIt can be proven that no longer equal subarrays can be created.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= nums.length</code></li>\n\t<li><code>0 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
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"code": "# @param {Integer[]} nums\n# @param {Integer} k\n# @return {Integer}\ndef longest_equal_subarray(nums, k)\n \nend",
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"lang": "Rust",
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"code": "impl Solution {\n pub fn longest_equal_subarray(nums: Vec<i32>, k: i32) -> i32 {\n \n }\n}",
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"code": "defmodule Solution do\n @spec longest_equal_subarray(nums :: [integer], k :: integer) :: integer\n def longest_equal_subarray(nums, k) do\n\n end\nend",
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"hints": [
"<div class=\"_1l1MA\">For each number <code>x</code> in <code>nums</code>, create a sorted list <code>indices<sub>x</sub></code> of all indices <code>i</code> such that <code>nums[i] == x</code>.</div>",
"<div class=\"_1l1MA\">On every <code>indices<sub>x</sub></code>, execute a sliding window technique.</div>",
"<div class=\"_1l1MA\">For each <code>indices<sub>x</sub></code>, find <code>i, j</code> such that <code>(indices<sub>x</sub>[j] - indices<sub>x</sub>[i]) - (j - i) <= k</code> and <code>j - i + 1</code> is maximized.</div>",
"<div class=\"_1l1MA\">The answer would be the maximum of <code>j - i + 1</code> for all <code>indices<sub>x</sub></code>.</div>"
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