leetcode-problemset/leetcode/originData/execute-asynchronous-functions-in-parallel.json

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            "title": "Execute Asynchronous Functions in Parallel",
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            "content": "<p>Given an array of&nbsp;asynchronous functions&nbsp;<code>functions</code>, return a new promise <code>promise</code>. Each function in the array accepts no arguments&nbsp;and returns a promise. All the promises should be executed in parallel.</p>\n\n<p><code>promise</code> resolves:</p>\n\n<ul>\n\t<li>When all the promises returned from&nbsp;<code>functions</code>&nbsp;were resolved successfully in parallel.&nbsp;The resolved&nbsp;value of&nbsp;<code>promise</code> should be an array of all the resolved values of promises in the same order as they were in the&nbsp;<code>functions</code>. The <code>promise</code> should resolve when all the asynchronous functions in the array have completed execution in parallel.</li>\n</ul>\n\n<p><code>promise</code> rejects:</p>\n\n<ul>\n\t<li>When any&nbsp;of the promises&nbsp;returned from&nbsp;<code>functions</code>&nbsp;were rejected.&nbsp;<code>promise</code> should also&nbsp;reject&nbsp;with the reason of the first rejection.</li>\n</ul>\n\n<p>Please solve it without using the built-in&nbsp;<code>Promise.all</code>&nbsp;function.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n&nbsp; () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(5), 200))\n]\n<strong>Output:</strong> {&quot;t&quot;: 200, &quot;resolved&quot;: [5]}\n<strong>Explanation:</strong> \npromiseAll(functions).then(console.log); // [5]\n\nThe single function was resolved at 200ms with a value of 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(1), 200)), \n    () =&gt; new Promise((resolve, reject) =&gt; setTimeout(() =&gt; reject(&quot;Error&quot;), 100))\n]\n<strong>Output:</strong> {&quot;t&quot;: 100, &quot;rejected&quot;: &quot;Error&quot;}\n<strong>Explanation:</strong> Since one of the promises rejected, the returned promise also rejected with the same error at the same time.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(4), 50)), \n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(10), 150)), \n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(16), 100))\n]\n<strong>Output:</strong> {&quot;t&quot;: 150, &quot;resolved&quot;: [4, 10, 16]}\n<strong>Explanation:</strong> All the promises resolved with a value. The returned promise resolved when the last promise resolved.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>functions</code>&nbsp;is an array of functions that returns promises</li>\n\t<li><code>1 &lt;= functions.length &lt;= 10</code></li>\n</ul>\n",
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                    "code": "/**\n * @param {Array<Function>} functions\n * @return {Promise<any>}\n */\nvar promiseAll = function(functions) {\n    \n};\n\n/**\n * const promise = promiseAll([() => new Promise(res => res(42))])\n * promise.then(console.log); // [42]\n */",
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                    "code": "type Fn<T> = () => Promise<T>\n\nfunction promiseAll<T>(functions: Fn<T>[]): Promise<T[]> {\n\t\n};\n\n/**\n * const promise = promiseAll([() => new Promise(res => res(42))])\n * promise.then(console.log); // [42]\n */",
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