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< p > Given the < code > root< / code > of a binary tree, the level of its root is < code > 1< / code > , the level of its children is < code > 2< / code > , and so on.< / p >
< p > Return the < strong > smallest< / strong > level < code > x< / code > such that the sum of all the values of nodes at level < code > x< / code > is < strong > maximal< / strong > .< / p >
< p > < / p >
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< p > < strong class = "example" > Example 1:< / strong > < / p >
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< img alt = "" src = "https://assets.leetcode.com/uploads/2019/05/03/capture.JPG" style = "width: 200px; height: 175px;" / >
< pre >
< strong > Input:< / strong > root = [1,7,0,7,-8,null,null]
< strong > Output:< / strong > 2
< strong > Explanation: < / strong >
Level 1 sum = 1.
Level 2 sum = 7 + 0 = 7.
Level 3 sum = 7 + -8 = -1.
So we return the level with the maximum sum which is level 2.
< / pre >
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< p > < strong class = "example" > Example 2:< / strong > < / p >
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< pre >
< strong > Input:< / strong > root = [989,null,10250,98693,-89388,null,null,null,-32127]
< strong > Output:< / strong > 2
< / pre >
< p > < / p >
< p > < strong > Constraints:< / strong > < / p >
< ul >
< li > The number of nodes in the tree is in the range < code > [1, 10< sup > 4< / sup > ]< / code > .< / li >
< li > < code > -10< sup > 5< / sup > < = Node.val < = 10< sup > 5< / sup > < / code > < / li >
< / ul >