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leetcode-problemset/leetcode-cn/problem (Chinese)/N 字形变换 [zigzag-conversion].html

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2022-03-27 20:56:26 +08:00
<p>将一个给定字符串 <code>s</code> 根据给定的行数 <code>numRows</code> 以从上往下、从左到右进行 Z 字形排列。</p>
<p>比如输入字符串为 <code>"PAYPALISHIRING"</code> 行数为 <code>3</code> 时,排列如下:</p>
<pre>
P A H N
A P L S I I G
Y I R</pre>
<p>之后,你的输出需要从左往右逐行读取,产生出一个新的字符串,比如:<code>"PAHNAPLSIIGYIR"</code></p>
<p>请你实现这个将字符串进行指定行数变换的函数:</p>
<pre>
string convert(string s, int numRows);</pre>
<p> </p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>s = "PAYPALISHIRING", numRows = 3
<strong>输出:</strong>"PAHNAPLSIIGYIR"
</pre>
<strong>示例 2</strong>
<pre>
<strong>输入:</strong>s = "PAYPALISHIRING", numRows = 4
<strong>输出:</strong>"PINALSIGYAHRPI"
<strong>解释:</strong>
P I N
A L S I G
Y A H R
P I
</pre>
<p><strong>示例 3</strong></p>
<pre>
<strong>输入:</strong>s = "A", numRows = 1
<strong>输出:</strong>"A"
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 <= s.length <= 1000</code></li>
<li><code>s</code> 由英文字母(小写和大写)、<code>','</code><code>'.'</code> 组成</li>
<li><code>1 <= numRows <= 1000</code></li>
</ul>