leetcode-problemset/leetcode-cn/originData/execute-asynchronous-functions-in-parallel.json

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            "title": "Execute Asynchronous Functions in Parallel",
            "titleSlug": "execute-asynchronous-functions-in-parallel",
            "content": "<p>Given an array of&nbsp;asynchronous functions&nbsp;<code>functions</code>, return a new promise <code>promise</code>. Each function in the array accepts no arguments&nbsp;and returns a promise. All the promises should be executed in parallel.</p>\n\n<p><code>promise</code> resolves:</p>\n\n<ul>\n\t<li>When all the promises returned from&nbsp;<code>functions</code>&nbsp;were resolved successfully in parallel.&nbsp;The resolved&nbsp;value of&nbsp;<code>promise</code> should be an array of all the resolved values of promises in the same order as they were in the&nbsp;<code>functions</code>. The <code>promise</code> should resolve when all the asynchronous functions in the array have completed execution in parallel.</li>\n</ul>\n\n<p><code>promise</code> rejects:</p>\n\n<ul>\n\t<li>When any&nbsp;of the promises&nbsp;returned from&nbsp;<code>functions</code>&nbsp;were rejected.&nbsp;<code>promise</code> should also&nbsp;reject&nbsp;with the reason of the first rejection.</li>\n</ul>\n\n<p>Please solve it without using the built-in&nbsp;<code>Promise.all</code>&nbsp;function.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n&nbsp; () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(5), 200))\n]\n<strong>Output:</strong> {&quot;t&quot;: 200, &quot;resolved&quot;: [5]}\n<strong>Explanation:</strong> \npromiseAll(functions).then(console.log); // [5]\n\nThe single function was resolved at 200ms with a value of 5.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(1), 200)), \n    () =&gt; new Promise((resolve, reject) =&gt; setTimeout(() =&gt; reject(&quot;Error&quot;), 100))\n]\n<strong>Output:</strong> {&quot;t&quot;: 100, &quot;rejected&quot;: &quot;Error&quot;}\n<strong>Explanation:</strong> Since one of the promises rejected, the returned promise also rejected with the same error at the same time.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> functions = [\n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(4), 50)), \n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(10), 150)), \n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(16), 100))\n]\n<strong>Output:</strong> {&quot;t&quot;: 150, &quot;resolved&quot;: [4, 10, 16]}\n<strong>Explanation:</strong> All the promises resolved with a value. The returned promise resolved when the last promise resolved.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>functions</code>&nbsp;is an array of functions that returns promises</li>\n\t<li><code>1 &lt;= functions.length &lt;= 10</code></li>\n</ul>\n",
            "translatedTitle": "并行执行异步函数",
            "translatedContent": "<p>给定一个异步函数数组 <code>functions</code>，返回一个新的 promise 对象&nbsp;<code>promise</code>。数组中的每个函数都不接受参数并返回一个 promise。所有的 promise 都应该并行执行。</p>\n\n<p><code>promise</code> resolve 条件：</p>\n\n<ul>\n\t<li>当所有从 <code>functions</code> 返回的 promise 都成功的并行解析时。<code>promise</code> 的解析值应该是一个按照它们在 <code>functions</code> 中的顺序排列的 promise 的解析值数组。<code>promise</code> 应该在数组中的所有异步函数并行执行完成时解析。</li>\n</ul>\n\n<p><code>promise</code>&nbsp;reject 条件：</p>\n\n<ul>\n\t<li>当任何从 <code>functions</code> 返回的 promise 被拒绝时。<code>promise</code> 也会被拒绝，并返回第一个拒绝的原因。</li>\n</ul>\n\n<p>请在不使用内置的 <code>Promise.all</code> 函数的情况下解决。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>functions = [\n&nbsp; () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(5), 200))\n]\n<b>输出：</b>{\"t\": 200, \"resolved\": [5]}\n<b>解释：</b>\npromiseAll(functions).then(console.log); // [5]\n\n单个函数在 200 毫秒后以值 5 成功解析。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>functions = [\n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(1), 200)), \n    () =&gt; new Promise((resolve, reject) =&gt; setTimeout(() =&gt; reject(\"Error\"), 100))\n]\n<b>输出：</b>{\"t\": 100, \"rejected\": \"Error\"}\n<b>解释：</b>由于其中一个 promise 被拒绝，返回的 promise 也在同一时间被拒绝并返回相同的错误。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>functions = [\n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(4), 50)), \n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(10), 150)), \n    () =&gt; new Promise(resolve =&gt; setTimeout(() =&gt; resolve(16), 100))\n]\n<b>输出：</b>{\"t\": 150, \"resolved\": [4, 10, 16]}\n<b>解释：</b>所有的 promise 都成功执行。当最后一个 promise 被解析时，返回的 promise 也被解析了。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>函数 <code>functions</code> 是一个返回 promise 的函数数组</li>\n\t<li><code>1 &lt;= functions.length &lt;= 10</code></li>\n</ul>\n",
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