mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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205 lines
18 KiB
JSON
205 lines
18 KiB
JSON
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"title": "Number of Pairs Satisfying Inequality",
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"content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code>, each of size <code>n</code>, and an integer <code>diff</code>. Find the number of <strong>pairs</strong> <code>(i, j)</code> such that:</p>\n\n<ul>\n\t<li><code>0 <= i < j <= n - 1</code> <strong>and</strong></li>\n\t<li><code>nums1[i] - nums1[j] <= nums2[i] - nums2[j] + diff</code>.</li>\n</ul>\n\n<p>Return<em> the <strong>number of pairs</strong> that satisfy the conditions.</em></p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [3,2,5], nums2 = [2,2,1], diff = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nThere are 3 pairs that satisfy the conditions:\n1. i = 0, j = 1: 3 - 2 <= 2 - 2 + 1. Since i < j and 1 <= 1, this pair satisfies the conditions.\n2. i = 0, j = 2: 3 - 5 <= 2 - 1 + 1. Since i < j and -2 <= 2, this pair satisfies the conditions.\n3. i = 1, j = 2: 2 - 5 <= 2 - 1 + 1. Since i < j and -3 <= 2, this pair satisfies the conditions.\nTherefore, we return 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [3,-1], nums2 = [-2,2], diff = -1\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nSince there does not exist any pair that satisfies the conditions, we return 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length == nums2.length</code></li>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= nums1[i], nums2[i] <= 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>4</sup> <= diff <= 10<sup>4</sup></code></li>\n</ul>\n",
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"exampleTestcases": "[3,2,5]\n[2,2,1]\n1\n[3,-1]\n[-2,2]\n-1",
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"categoryTitle": "Algorithms",
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"code": "class Solution {\npublic:\n long long numberOfPairs(vector<int>& nums1, vector<int>& nums2, int diff) {\n \n }\n};",
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"code": "class Solution(object):\n def numberOfPairs(self, nums1, nums2, diff):\n \"\"\"\n :type nums1: List[int]\n :type nums2: List[int]\n :type diff: int\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * @param {number[]} nums1\n * @param {number[]} nums2\n * @param {number} diff\n * @return {number}\n */\nvar numberOfPairs = function(nums1, nums2, diff) {\n \n};",
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"code": "# @param {Integer[]} nums1\n# @param {Integer[]} nums2\n# @param {Integer} diff\n# @return {Integer}\ndef number_of_pairs(nums1, nums2, diff)\n \nend",
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"hints": [
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"Try rearranging the equation.",
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"Once the equation is rearranged properly, think how a segment tree or a Fenwick tree can be used to solve the rearranged equation.",
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"Iterate through the array backwards."
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],
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