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"title": "Minimum Window Substring",
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"content": "<p>Given two strings <code>s</code> and <code>t</code> of lengths <code>m</code> and <code>n</code> respectively, return <em>the <strong>minimum window substring</strong> of </em><code>s</code><em> such that every character in </em><code>t</code><em> (<strong>including duplicates</strong>) is included in the window. If there is no such substring</em><em>, return the empty string </em><code>&quot;&quot;</code><em>.</em></p>\n\n<p>The testcases will be generated such that the answer is <strong>unique</strong>.</p>\n\n<p>A <strong>substring</strong> is a contiguous sequence of characters within the string.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ADOBECODEBANC&quot;, t = &quot;ABC&quot;\n<strong>Output:</strong> &quot;BANC&quot;\n<strong>Explanation:</strong> The minimum window substring &quot;BANC&quot; includes &#39;A&#39;, &#39;B&#39;, and &#39;C&#39; from string t.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, t = &quot;a&quot;\n<strong>Output:</strong> &quot;a&quot;\n<strong>Explanation:</strong> The entire string s is the minimum window.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;a&quot;, t = &quot;aa&quot;\n<strong>Output:</strong> &quot;&quot;\n<strong>Explanation:</strong> Both &#39;a&#39;s from t must be included in the window.\nSince the largest window of s only has one &#39;a&#39;, return empty string.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == s.length</code></li>\n\t<li><code>n == t.length</code></li>\n\t<li><code>1 &lt;= m, n&nbsp;&lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> and <code>t</code> consist of uppercase and lowercase English letters.</li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>Follow up:</strong> Could you find an algorithm that runs in <code>O(m + n)</code> time?",
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"hints": [
"Use two pointers to create a window of letters in <b>S</b>, which would have all the characters from <b>T</b>.",
"Since you have to find the minimum window in <b>S</b> which has all the characters from <b>T</b>, you need to expand and contract the window using the two pointers and keep checking the window for all the characters. This approach is also called Sliding Window Approach.\r\n\r\n<br><br>\r\n<pre>\r\nL ------------------------ R , Suppose this is the window that contains all characters of <b>T</b> \r\n \r\n&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp L----------------- R , this is the contracted window. We found a smaller window that still contains all the characters in <b>T</b>\r\n\r\nWhen the window is no longer valid, start expanding again using the right pointer. </pre>"
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"sampleTestCase": "\"ADOBECODEBANC\"\n\"ABC\"",
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