mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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198 lines
17 KiB
JSON
198 lines
17 KiB
JSON
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"title": "Divide Intervals Into Minimum Number of Groups",
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"content": "<p>You are given a 2D integer array <code>intervals</code> where <code>intervals[i] = [left<sub>i</sub>, right<sub>i</sub>]</code> represents the <strong>inclusive</strong> interval <code>[left<sub>i</sub>, right<sub>i</sub>]</code>.</p>\n\n<p>You have to divide the intervals into one or more <strong>groups</strong> such that each interval is in <strong>exactly</strong> one group, and no two intervals that are in the same group <strong>intersect</strong> each other.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of groups you need to make</em>.</p>\n\n<p>Two intervals <strong>intersect</strong> if there is at least one common number between them. For example, the intervals <code>[1, 5]</code> and <code>[5, 8]</code> intersect.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[5,10],[6,8],[1,5],[2,3],[1,10]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can divide the intervals into the following groups:\n- Group 1: [1, 5], [6, 8].\n- Group 2: [2, 3], [5, 10].\n- Group 3: [1, 10].\nIt can be proven that it is not possible to divide the intervals into fewer than 3 groups.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,3],[5,6],[8,10],[11,13]]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> None of the intervals overlap, so we can put all of them in one group.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= intervals.length <= 10<sup>5</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>1 <= left<sub>i</sub> <= right<sub>i</sub> <= 10<sup>6</sup></code></li>\n</ul>\n",
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"code": "class Solution(object):\n def minGroups(self, intervals):\n \"\"\"\n :type intervals: List[List[int]]\n :rtype: int\n \"\"\"\n ",
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"code": "\n\nint minGroups(int** intervals, int intervalsSize, int* intervalsColSize){\n\n}",
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"lang": "C#",
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"langSlug": "csharp",
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"code": "public class Solution {\n public int MinGroups(int[][] intervals) {\n \n }\n}",
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"lang": "JavaScript",
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"code": "/**\n * @param {number[][]} intervals\n * @return {number}\n */\nvar minGroups = function(intervals) {\n \n};",
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"lang": "Ruby",
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"langSlug": "ruby",
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"code": "# @param {Integer[][]} intervals\n# @return {Integer}\ndef min_groups(intervals)\n \nend",
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"lang": "Scala",
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"langSlug": "scala",
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"code": "object Solution {\n def minGroups(intervals: Array[Array[Int]]): Int = {\n \n }\n}",
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"lang": "Kotlin",
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"code": "class Solution {\n fun minGroups(intervals: Array<IntArray>): Int {\n \n }\n}",
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"lang": "Rust",
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"langSlug": "rust",
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"code": "impl Solution {\n pub fn min_groups(intervals: Vec<Vec<i32>>) -> i32 {\n \n }\n}",
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"code": "class Solution {\n\n /**\n * @param Integer[][] $intervals\n * @return Integer\n */\n function minGroups($intervals) {\n \n }\n}",
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"code": "class Solution {\n int minGroups(List<List<int>> intervals) {\n\n }\n}",
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"Can you find a different way to describe the question?",
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"The minimum number of groups we need is equivalent to the maximum number of intervals that overlap at some point. How can you find that?"
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