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leetcode-problemset/leetcode-cn/originData/rearrange-products-table.json

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{
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"question": {
"questionId": "1948",
"questionFrontendId": "1795",
"categoryTitle": "Database",
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"title": "Rearrange Products Table",
"titleSlug": "rearrange-products-table",
"content": "<p>Table: <code>Products</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| product_id | int |\n| store1 | int |\n| store2 | int |\n| store3 | int |\n+-------------+---------+\nproduct_id is the primary key for this table.\nEach row in this table indicates the product&#39;s price in 3 different stores: store1, store2, and store3.\nIf the product is not available in a store, the price will be null in that store&#39;s column.\n</pre>\n\n<p>&nbsp;</p>\n\n<p>Write an SQL query to rearrange the <code>Products</code> table so that each row has <code>(product_id, store, price)</code>. If a product is not available in a store, do <strong>not</strong> include a row with that <code>product_id</code> and <code>store</code> combination in the result table.</p>\n\n<p>Return the result table in <strong>any order</strong>.</p>\n\n<p>The query result format is in the following example.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nProducts table:\n+------------+--------+--------+--------+\n| product_id | store1 | store2 | store3 |\n+------------+--------+--------+--------+\n| 0 | 95 | 100 | 105 |\n| 1 | 70 | null | 80 |\n+------------+--------+--------+--------+\n<strong>Output:</strong> \n+------------+--------+-------+\n| product_id | store | price |\n+------------+--------+-------+\n| 0 | store1 | 95 |\n| 0 | store2 | 100 |\n| 0 | store3 | 105 |\n| 1 | store1 | 70 |\n| 1 | store3 | 80 |\n+------------+--------+-------+\n<strong>Explanation:</strong> \nProduct 0 is available in all three stores with prices 95, 100, and 105 respectively.\nProduct 1 is available in store1 with price 70 and store3 with price 80. The product is not available in store2.\n</pre>\n",
"translatedTitle": "每个产品在不同商店的价格",
"translatedContent": "<p>表:<code>Products</code></p>\n\n<pre>\n+-------------+---------+\n| Column Name | Type |\n+-------------+---------+\n| product_id | int |\n| store1 | int |\n| store2 | int |\n| store3 | int |\n+-------------+---------+\n这张表的主键是product_id产品Id。\n每行存储了这一产品在不同商店store1, store2, store3的价格。\n如果这一产品在商店里没有出售则值将为null。\n</pre>\n\n<p>&nbsp;</p>\n\n<p>请你重构 <code>Products</code> 表,查询每个产品在不同商店的价格,使得输出的格式变为<code>(product_id, store, price)</code> 。如果这一产品在商店里没有出售,则不输出这一行。</p>\n\n<p>输出结果表中的 <strong>顺序不作要求</strong> 。</p>\n\n<p>查询输出格式请参考下面示例。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>\nProducts table:\n+------------+--------+--------+--------+\n| product_id | store1 | store2 | store3 |\n+------------+--------+--------+--------+\n| 0 | 95 | 100 | 105 |\n| 1 | 70 | null | 80 |\n+------------+--------+--------+--------+\n<strong>输出:</strong>\n+------------+--------+-------+\n| product_id | store | price |\n+------------+--------+-------+\n| 0 | store1 | 95 |\n| 0 | store2 | 100 |\n| 0 | store3 | 105 |\n| 1 | store1 | 70 |\n| 1 | store3 | 80 |\n+------------+--------+-------+\n<strong>解释:</strong>\n产品0在store1store2,store3的价格分别为95,100,105。\n产品1在store1store3的价格分别为70,80。在store2无法买到。</pre>\n",
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"code": "# Write your MySQL query statement below",
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"hints": [],
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"sampleTestCase": "{\"headers\":{\"Products\":[\"product_id\",\"store1\",\"store2\",\"store3\"]},\"rows\":{\"Products\":[[0, 95, 100, 105], [1, 70, null, 80]]}}",
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"Truncate table Products",
"insert into Products (product_id, store1, store2, store3) values ('0', '95', '100', '105')",
"insert into Products (product_id, store1, store2, store3) values ('1', '70', 'None', '80')"
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"exampleTestcases": "{\"headers\":{\"Products\":[\"product_id\",\"store1\",\"store2\",\"store3\"]},\"rows\":{\"Products\":[[0, 95, 100, 105], [1, 70, null, 80]]}}",
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