mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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51 lines
12 KiB
JSON
51 lines
12 KiB
JSON
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{
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"data": {
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"question": {
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"questionId": "2490",
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"questionFrontendId": "2355",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1703643,
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"title": "Maximum Number of Books You Can Take",
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"titleSlug": "maximum-number-of-books-you-can-take",
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"content": null,
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"translatedTitle": null,
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"translatedContent": null,
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"isPaidOnly": true,
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"difficulty": "Hard",
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"likes": 1,
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"dislikes": 0,
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"isLiked": null,
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"similarQuestions": "[]",
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"contributors": [],
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"topicTags": [],
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"companyTagStats": null,
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"codeSnippets": null,
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"stats": "{\"totalAccepted\": \"58\", \"totalSubmission\": \"77\", \"totalAcceptedRaw\": 58, \"totalSubmissionRaw\": 77, \"acRate\": \"75.3%\"}",
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"hints": [
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"Create a dp array where dp[i] is the maximum number of books you can take if you can only take books from bookshelves 0 to i and you must take books from bookshelf i.",
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"Keep taking as many books as you can (i.e. starting from bookshelf i and going backwards, you take arr[i], arr[i] - 1, arr[i] - 2, … books).",
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"You may reach an index j where arr[j] < arr[i] - (i - j). Have we already found the maximum number of books you can take from bookshelves 0 to j? How do we quickly find such an index j?",
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"Keep a stack of possible indices for j. If x is the number at the top of the stack, keep popping from the stack while arr[x] ≥ arr[i] - (i - x). This is because if the inequality mentioned before is true, x will never be an index j as index i will run out of items first."
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],
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"solution": null,
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"status": null,
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"sampleTestCase": "[8,5,2,7,9]",
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"metaData": "{\n \"name\": \"maximumBooks\",\n \"params\": [\n {\n \"name\": \"books\",\n \"type\": \"integer[]\"\n }\n ],\n \"return\": {\n \"type\": \"long\"\n }\n}",
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"judgerAvailable": true,
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"judgeType": "large",
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"mysqlSchemas": [],
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"enableRunCode": true,
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"book": null,
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"editorType": "CKEDITOR",
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"style": "LEETCODE",
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"exampleTestcases": "[8,5,2,7,9]\n[7,0,3,4,5]\n[8,2,3,7,3,4,0,1,4,3]",
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"__typename": "QuestionNode"
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}
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}
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}
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