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leetcode-problemset/leetcode-cn/problem (Chinese)/驼峰式匹配 [camelcase-matching].html

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2022-03-27 20:46:41 +08:00
<p>如果我们可以将<strong>小写字母</strong>插入模式串&nbsp;<code>pattern</code>&nbsp;得到待查询项&nbsp;<code>query</code>,那么待查询项与给定模式串匹配。(我们可以在任何位置插入每个字符,也可以插入 0 个字符。)</p>
<p>给定待查询列表&nbsp;<code>queries</code>,和模式串&nbsp;<code>pattern</code>,返回由布尔值组成的答案列表&nbsp;<code>answer</code>。只有在待查项&nbsp;<code>queries[i]</code> 与模式串&nbsp;<code>pattern</code> 匹配时,&nbsp;<code>answer[i]</code>&nbsp;才为 <code>true</code>,否则为 <code>false</code></p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre><strong>输入:</strong>queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FB&quot;
<strong>输出:</strong>[true,false,true,true,false]
<strong>示例:</strong>
&quot;FooBar&quot; 可以这样生成:&quot;F&quot; + &quot;oo&quot; + &quot;B&quot; + &quot;ar&quot;
&quot;FootBall&quot; 可以这样生成:&quot;F&quot; + &quot;oot&quot; + &quot;B&quot; + &quot;all&quot;.
&quot;FrameBuffer&quot; 可以这样生成:&quot;F&quot; + &quot;rame&quot; + &quot;B&quot; + &quot;uffer&quot;.</pre>
<p><strong>示例 2</strong></p>
<pre><strong>输入:</strong>queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FoBa&quot;
<strong>输出:</strong>[true,false,true,false,false]
<strong>解释:</strong>
&quot;FooBar&quot; 可以这样生成:&quot;Fo&quot; + &quot;o&quot; + &quot;Ba&quot; + &quot;r&quot;.
&quot;FootBall&quot; 可以这样生成:&quot;Fo&quot; + &quot;ot&quot; + &quot;Ba&quot; + &quot;ll&quot;.
</pre>
<p><strong>示例 3</strong></p>
<pre><strong>输出:</strong>queries = [&quot;FooBar&quot;,&quot;FooBarTest&quot;,&quot;FootBall&quot;,&quot;FrameBuffer&quot;,&quot;ForceFeedBack&quot;], pattern = &quot;FoBaT&quot;
<strong>输入:</strong>[false,true,false,false,false]
<strong>解释: </strong>
&quot;FooBarTest&quot; 可以这样生成:&quot;Fo&quot; + &quot;o&quot; + &quot;Ba&quot; + &quot;r&quot; + &quot;T&quot; + &quot;est&quot;.
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ol>
<li><code>1 &lt;= queries.length &lt;= 100</code></li>
<li><code>1 &lt;= queries[i].length &lt;= 100</code></li>
<li><code>1 &lt;= pattern.length &lt;= 100</code></li>
<li>所有字符串都仅由大写和小写英文字母组成。</li>
</ol>