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leetcode-problemset/leetcode-cn/problem (Chinese)/最大单词长度乘积 [maximum-product-of-word-lengths].html

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2022-03-27 20:56:26 +08:00
<p>给你一个字符串数组&nbsp;<code>words</code> ,找出并返回 <code>length(words[i]) * length(words[j])</code>&nbsp;的最大值,并且这两个单词不含有公共字母。如果不存在这样的两个单词,返回 <code>0</code></p>
<p>&nbsp;</p>
<p><strong>示例&nbsp;1</strong></p>
<pre>
<strong>输入:</strong>words = <code>["abcw","baz","foo","bar","xtfn","abcdef"]</code>
<strong>输出:</strong><code>16
<strong>解释</strong></code><strong></strong><code>这两个单词为<strong> </strong>"abcw", "xtfn"</code></pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>words = <code>["a","ab","abc","d","cd","bcd","abcd"]</code>
<strong>输出:</strong><code>4
<strong>解释</strong></code><strong></strong>这两个单词为 <code>"ab", "cd"</code></pre>
<p><strong>示例 3</strong></p>
<pre>
<strong>输入:</strong>words = <code>["a","aa","aaa","aaaa"]</code>
<strong>输出:</strong><code>0
<strong>解释</strong></code><strong></strong><code>不存在这样的两个单词。</code>
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>2 &lt;= words.length &lt;= 1000</code></li>
<li><code>1 &lt;= words[i].length &lt;= 1000</code></li>
<li><code>words[i]</code>&nbsp;仅包含小写字母</li>
</ul>