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2022-03-27 20:38:29 +08:00
<p>给定一个二叉树的根节点 <code>root</code>&nbsp;,和一个整数 <code>targetSum</code> ,求该二叉树里节点值之和等于 <code>targetSum</code><strong>路径</strong> 的数目。</p>
<p><strong>路径</strong> 不需要从根节点开始,也不需要在叶子节点结束,但是路径方向必须是向下的(只能从父节点到子节点)。</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg" style="width: 452px; " /></p>
<pre>
<strong>输入:</strong>root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8
<strong>输出:</strong>3
<strong>解释:</strong>和等于 8 的路径有 3 条,如图所示。
</pre>
<p><strong>示例 2</strong></p>
<pre>
<strong>输入:</strong>root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22
<strong>输出:</strong>3
</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li>二叉树的节点个数的范围是 <code>[0,1000]</code></li>
<li><meta charset="UTF-8" /><code>-10<sup><span style="font-size: 9.449999809265137px;">9</span></sup>&nbsp;&lt;= Node.val &lt;= 10<sup><span style="font-size: 9.449999809265137px;">9</span></sup></code>&nbsp;</li>
<li><code>-1000&nbsp;&lt;= targetSum&nbsp;&lt;= 1000</code>&nbsp;</li>
</ul>
<p>&nbsp;</p>
<p><meta charset="UTF-8" />注意:本题与主站 437&nbsp;题相同:<a href="https://leetcode-cn.com/problems/path-sum-iii/">https://leetcode-cn.com/problems/path-sum-iii/</a></p>