2023-12-09 18:42:21 +08:00
|
|
|
|
<p>给定一个 24 小时制(小时:分钟 <strong>"HH:MM"</strong>)的时间列表,找出列表中任意两个时间的最小时间差并以分钟数表示。</p>
|
2022-03-27 20:38:29 +08:00
|
|
|
|
|
|
|
|
|
<p> </p>
|
|
|
|
|
|
|
|
|
|
<p><strong>示例 1:</strong></p>
|
|
|
|
|
|
|
|
|
|
<pre>
|
2023-12-09 18:42:21 +08:00
|
|
|
|
<strong>输入:</strong>timePoints = ["23:59","00:00"]
|
2022-03-27 20:38:29 +08:00
|
|
|
|
<strong>输出:</strong>1
|
|
|
|
|
</pre>
|
|
|
|
|
|
|
|
|
|
<p><strong>示例 2:</strong></p>
|
|
|
|
|
|
|
|
|
|
<pre>
|
2023-12-09 18:42:21 +08:00
|
|
|
|
<strong>输入:</strong>timePoints = ["00:00","23:59","00:00"]
|
2022-03-27 20:38:29 +08:00
|
|
|
|
<strong>输出:</strong>0
|
|
|
|
|
</pre>
|
|
|
|
|
|
|
|
|
|
<p> </p>
|
|
|
|
|
|
|
|
|
|
<p><strong>提示:</strong></p>
|
|
|
|
|
|
|
|
|
|
<ul>
|
2023-12-09 18:42:21 +08:00
|
|
|
|
<li><code>2 <= timePoints.length <= 2 * 10<sup>4</sup></code></li>
|
|
|
|
|
<li><code>timePoints[i]</code> 格式为 <strong>"HH:MM"</strong></li>
|
2022-03-27 20:38:29 +08:00
|
|
|
|
</ul>
|
|
|
|
|
|
|
|
|
|
<p> </p>
|
|
|
|
|
|
|
|
|
|
<p><meta charset="UTF-8" />注意:本题与主站 539 题相同: <a href="https://leetcode-cn.com/problems/minimum-time-difference/">https://leetcode-cn.com/problems/minimum-time-difference/</a></p>
|