mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
42 lines
2.5 KiB
HTML
42 lines
2.5 KiB
HTML
|
<p>给你一个数组 <code>favoriteCompanies</code> ，其中 <code>favoriteCompanies[i]</code> 是第 <code>i</code> 名用户收藏的公司清单（<strong>下标从 0 开始</strong>）。</p>
|
|||
|
|
|
|||
|
|
<p>请找出不是其他任何人收藏的公司清单的子集的收藏清单，并返回该清单下标<em>。</em>下标需要按升序排列<em>。</em></p>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>示例 1：</strong></p>
|
|||
|
|
|
|||
|
|
<pre><strong>输入：</strong>favoriteCompanies = [["leetcode","google","facebook"],["google","microsoft"],["google","facebook"],["google"],["amazon"]]
|
|||
|
|
<strong>输出：</strong>[0,1,4]
|
|||
|
|
<strong>解释：</strong>
|
|||
|
|
favoriteCompanies[2]=["google","facebook"] 是 favoriteCompanies[0]=["leetcode","google","facebook"] 的子集。
|
|||
|
|
favoriteCompanies[3]=["google"] 是 favoriteCompanies[0]=["leetcode","google","facebook"] 和 favoriteCompanies[1]=["google","microsoft"] 的子集。
|
|||
|
|
其余的收藏清单均不是其他任何人收藏的公司清单的子集，因此，答案为 [0,1,4] 。
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 2：</strong></p>
|
|||
|
|
|
|||
|
|
<pre><strong>输入：</strong>favoriteCompanies = [["leetcode","google","facebook"],["leetcode","amazon"],["facebook","google"]]
|
|||
|
|
<strong>输出：</strong>[0,1]
|
|||
|
|
<strong>解释：</strong>favoriteCompanies[2]=["facebook","google"] 是 favoriteCompanies[0]=["leetcode","google","facebook"] 的子集，因此，答案为 [0,1] 。
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 3：</strong></p>
|
|||
|
|
|
|||
|
|
<pre><strong>输入：</strong>favoriteCompanies = [["leetcode"],["google"],["facebook"],["amazon"]]
|
|||
|
|
<strong>输出：</strong>[0,1,2,3]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>提示：</strong></p>
|
|||
|
|
|
|||
|
|
<ul>
|
|||
|
|
<li><code>1 <= favoriteCompanies.length <= 100</code></li>
|
|||
|
|
<li><code>1 <= favoriteCompanies[i].length <= 500</code></li>
|
|||
|
|
<li><code>1 <= favoriteCompanies[i][j].length <= 20</code></li>
|
|||
|
|
<li><code>favoriteCompanies[i]</code> 中的所有字符串 <strong>各不相同</strong> 。</li>
|
|||
|
|
<li>用户收藏的公司清单也 <strong>各不相同</strong> ，也就是说，即便我们按字母顺序排序每个清单， <code>favoriteCompanies[i] != favoriteCompanies[j] </code>仍然成立。</li>
|
|||
|
|
<li>所有字符串仅包含小写英文字母。</li>
|
|||
|
|
</ul>
|