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leetcode-problemset/leetcode-cn/problem (Chinese)/合并区间 [merge-intervals].html

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<p>以数组 <code>intervals</code> 表示若干个区间的集合,其中单个区间为 <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> 。请你合并所有重叠的区间,并返回&nbsp;<em>一个不重叠的区间数组,该数组需恰好覆盖输入中的所有区间</em>&nbsp;</p>
<p>&nbsp;</p>
<p><strong>示例 1</strong></p>
<pre>
<strong>输入:</strong>intervals = [[1,3],[2,6],[8,10],[15,18]]
<strong>输出:</strong>[[1,6],[8,10],[15,18]]
<strong>解释:</strong>区间 [1,3] 和 [2,6] 重叠, 将它们合并为 [1,6].
</pre>
<p><strong>示例&nbsp;2</strong></p>
<pre>
<strong>输入:</strong>intervals = [[1,4],[4,5]]
<strong>输出:</strong>[[1,5]]
<strong>解释:</strong>区间 [1,4] 和 [4,5] 可被视为重叠区间。</pre>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= intervals.length &lt;= 10<sup>4</sup></code></li>
<li><code>intervals[i].length == 2</code></li>
<li><code>0 &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt;= 10<sup>4</sup></code></li>
</ul>