1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-01-11 02:58:13 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
leetcode-problemset/leetcode-cn/problem (Chinese)/单词搜索 [word-search].html

43 lines
1.8 KiB
HTML
Raw Normal View History

2022-03-27 20:56:26 +08:00
<p>给定一个 <code>m x n</code> 二维字符网格 <code>board</code> 和一个字符串单词 <code>word</code> 。如果 <code>word</code> 存在于网格中,返回 <code>true</code> ;否则,返回 <code>false</code></p>
<p>单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中“相邻”单元格是那些水平相邻或垂直相邻的单元格。同一个单元格内的字母不允许被重复使用。</p>
<p> </p>
<p><strong>示例 1</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/11/04/word2.jpg" style="width: 322px; height: 242px;" />
<pre>
<strong>输入:</strong>board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCCED"
<strong>输出:</strong>true
</pre>
<p><strong>示例 2</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/11/04/word-1.jpg" style="width: 322px; height: 242px;" />
<pre>
<strong>输入:</strong>board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "SEE"
<strong>输出:</strong>true
</pre>
<p><strong>示例 3</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/10/15/word3.jpg" style="width: 322px; height: 242px;" />
<pre>
<strong>输入:</strong>board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCB"
<strong>输出:</strong>false
</pre>
<p> </p>
<p><strong>提示:</strong></p>
<ul>
<li><code>m == board.length</code></li>
<li><code>n = board[i].length</code></li>
<li><code>1 <= m, n <= 6</code></li>
<li><code>1 <= word.length <= 15</code></li>
<li><code>board</code><code>word</code> 仅由大小写英文字母组成</li>
</ul>
<p> </p>
<p><strong>进阶:</strong>你可以使用搜索剪枝的技术来优化解决方案,使其在 <code>board</code> 更大的情况下可以更快解决问题?</p>