mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-27 18:50:26 +08:00
54 lines
1.6 KiB
HTML
54 lines
1.6 KiB
HTML
|
<p>给你一个<strong> 无重叠的</strong><em> ，</em>按照区间起始端点排序的区间列表。</p>
|
|||
|
|
|
|||
|
|
<p>在列表中插入一个新的区间，你需要确保列表中的区间仍然有序且不重叠（如果有必要的话，可以合并区间）。</p>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>示例 1：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>intervals = [[1,3],[6,9]], newInterval = [2,5]
|
|||
|
|
<strong>输出：</strong>[[1,5],[6,9]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 2：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]
|
|||
|
|
<strong>输出：</strong>[[1,2],[3,10],[12,16]]
|
|||
|
|
<strong>解释：</strong>这是因为新的区间 <code>[4,8]</code> 与 <code>[3,5],[6,7],[8,10]</code> 重叠。</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 3：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>intervals = [], newInterval = [5,7]
|
|||
|
|
<strong>输出：</strong>[[5,7]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 4：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>intervals = [[1,5]], newInterval = [2,3]
|
|||
|
|
<strong>输出：</strong>[[1,5]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p><strong>示例 5：</strong></p>
|
|||
|
|
|
|||
|
|
<pre>
|
|||
|
|
<strong>输入：</strong>intervals = [[1,5]], newInterval = [2,7]
|
|||
|
|
<strong>输出：</strong>[[1,7]]
|
|||
|
|
</pre>
|
|||
|
|
|
|||
|
|
<p> </p>
|
|||
|
|
|
|||
|
|
<p><strong>提示：</strong></p>
|
|||
|
|
|
|||
|
|
<ul>
|
|||
|
|
<li><code>0 <= intervals.length <= 10<sup>4</sup></code></li>
|
|||
|
|
<li><code>intervals[i].length == 2</code></li>
|
|||
|
|
<li><code>0 <= intervals[i][0] <= intervals[i][1] <= 10<sup>5</sup></code></li>
|
|||
|
|
<li><code>intervals</code> 根据 <code>intervals[i][0]</code> 按 <strong>升序</strong> 排列</li>
|
|||
|
|
<li><code>newInterval.length == 2</code></li>
|
|||
|
|
<li><code>0 <= newInterval[0] <= newInterval[1] <= 10<sup>5</sup></code></li>
|
|||
|
|
</ul>
|