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leetcode-problemset/leetcode/originData/k-concatenation-maximum-sum.json

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{
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"title": "K-Concatenation Maximum Sum",
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"content": "<p>Given an integer array <code>arr</code> and an integer <code>k</code>, modify the array by repeating it <code>k</code> times.</p>\n\n<p>For example, if <code>arr = [1, 2]</code> and <code>k = 3 </code>then the modified array will be <code>[1, 2, 1, 2, 1, 2]</code>.</p>\n\n<p>Return the maximum sub-array sum in the modified array. Note that the length of the sub-array can be <code>0</code> and its sum in that case is <code>0</code>.</p>\n\n<p>As the answer can be very large, return the answer <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,2], k = 3\n<strong>Output:</strong> 9\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [1,-2,1], k = 5\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> arr = [-1,-2], k = 7\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= arr.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>4</sup> &lt;= arr[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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"code": "class Solution(object):\n def kConcatenationMaxSum(self, arr, k):\n \"\"\"\n :type arr: List[int]\n :type k: int\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * @param {number[]} arr\n * @param {number} k\n * @return {number}\n */\nvar kConcatenationMaxSum = function(arr, k) {\n \n};",
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"code": "# @param {Integer[]} arr\n# @param {Integer} k\n# @return {Integer}\ndef k_concatenation_max_sum(arr, k)\n \nend",
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"code": "class Solution {\n\n /**\n * @param Integer[] $arr\n * @param Integer $k\n * @return Integer\n */\n function kConcatenationMaxSum($arr, $k) {\n \n }\n}",
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"code": "defmodule Solution do\n @spec k_concatenation_max_sum(arr :: [integer], k :: integer) :: integer\n def k_concatenation_max_sum(arr, k) do\n\n end\nend",
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"hints": [
"How to solve the problem for k=1 ?",
"Use Kadane's algorithm for k=1.",
"What are the possible cases for the answer ?",
"The answer is the maximum between, the answer for k=1, the sum of the whole array multiplied by k, or the maximum suffix sum plus the maximum prefix sum plus (k-2) multiplied by the whole array sum for k > 1."
],
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