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leetcode-problemset/leetcode/originData/count-negative-numbers-in-a-sorted-matrix.json

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{
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"title": "Count Negative Numbers in a Sorted Matrix",
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"content": "<p>Given a <code>m x n</code> matrix <code>grid</code> which is sorted in non-increasing order both row-wise and column-wise, return <em>the number of <strong>negative</strong> numbers in</em> <code>grid</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> grid = [[4,3,2,-1],[3,2,1,-1],[1,1,-1,-2],[-1,-1,-2,-3]]\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> There are 8 negatives number in the matrix.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> grid = [[3,2],[1,0]]\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == grid.length</code></li>\n\t<li><code>n == grid[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 100</code></li>\n\t<li><code>-100 &lt;= grid[i][j] &lt;= 100</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<strong>Follow up:</strong> Could you find an <code>O(n + m)</code> solution?",
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"code": "class Solution {\npublic:\n int countNegatives(vector<vector<int>>& grid) {\n \n }\n};",
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"code": "class Solution(object):\n def countNegatives(self, grid):\n \"\"\"\n :type grid: List[List[int]]\n :rtype: int\n \"\"\"\n ",
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"code": "/**\n * @param {number[][]} grid\n * @return {number}\n */\nvar countNegatives = function(grid) {\n \n};",
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"code": "# @param {Integer[][]} grid\n# @return {Integer}\ndef count_negatives(grid)\n \nend",
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"code": "(define/contract (count-negatives grid)\n (-> (listof (listof exact-integer?)) exact-integer?)\n\n )",
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"hints": [
"Use binary search for optimization or simply brute force."
],
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