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"title" : "Number of Ways to Split Array" ,
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"content" : "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code>.</p>\n\n<p><code>nums</code> contains a <strong>valid split</strong> at index <code>i</code> if the following are true:</p>\n\n<ul>\n\t<li>The sum of the first <code>i + 1</code> elements is <strong>greater than or equal to</strong> the sum of the last <code>n - i - 1</code> elements.</li>\n\t<li>There is <strong>at least one</strong> element to the right of <code>i</code>. That is, <code>0 <= i < n - 1</code>.</li>\n</ul>\n\n<p>Return <em>the number of <strong>valid splits</strong> in</em> <code>nums</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,4,-8,7]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> \nThere are three ways of splitting nums into two non-empty parts:\n- Split nums at index 0. Then, the first part is [10], and its sum is 10. The second part is [4,-8,7], and its sum is 3. Since 10 >= 3, i = 0 is a valid split.\n- Split nums at index 1. Then, the first part is [10,4], and its sum is 14. The second part is [-8,7], and its sum is -1. Since 14 >= -1, i = 1 is a valid split.\n- Split nums at index 2. Then, the first part is [10,4,-8], and its sum is 6. The second part is [7], and its sum is 7. Since 6 < 7, i = 2 is not a valid split.\nThus, the number of valid splits in nums is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,3,1,0]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> \nThere are two valid splits in nums:\n- Split nums at index 1. Then, the first part is [2,3], and its sum is 5. The second part is [1,0], and its sum is 1. Since 5 >= 1, i = 1 is a valid split. \n- Split nums at index 2. Then, the first part is [2,3,1], and its sum is 6. The second part is [0], and its sum is 0. Since 6 >= 0, i = 2 is a valid split.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n" ,
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"translatedTitle" : "分割数组的方案数" ,
"translatedContent" : "<p>给你一个下标从 <strong>0</strong> 开始长度为 <code>n</code> 的整数数组 <code>nums</code> 。<br />\n<span style=\"\">如果以下描述为真,那么</span><span style=\"\"> </span><code>nums</code> 在下标 <code>i</code> 处有一个 <strong>合法的分割</strong> : </p>\n\n<ul>\n\t<li>前 <code>i + 1</code> 个元素的和 <strong>大于等于</strong> 剩下的 <code>n - i - 1</code> 个元素的和。</li>\n\t<li>下标 <code>i</code> 的右边 <strong>至少有一个</strong> 元素,也就是说下标 <code>i</code> 满足 <code>0 <= i < n - 1</code> 。</li>\n</ul>\n\n<p>请你返回 <code>nums</code> 中的 <strong>合法分割</strong> 方案数。</p>\n\n<p> </p>\n\n<p><strong>示例 1: </strong></p>\n\n<pre>\n<b>输入:</b>nums = [10,4,-8,7]\n<b>输出:</b>2\n<b>解释:</b>\n总共有 3 种不同的方案可以将 nums 分割成两个非空的部分:\n- 在下标 0 处分割 nums 。那么第一部分为 [10] ,和为 10 。第二部分为 [4,-8,7] ,和为 3 。因为 10 >= 3 ,所以 i = 0 是一个合法的分割。\n- 在下标 1 处分割 nums 。那么第一部分为 [10,4] ,和为 14 。第二部分为 [-8,7] ,和为 -1 。因为 14 >= -1 ,所以 i = 1 是一个合法的分割。\n- 在下标 2 处分割 nums 。那么第一部分为 [10,4,-8] ,和为 6 。第二部分为 [7] ,和为 7 。因为 6 < 7 ,所以 i = 2 不是一个合法的分割。\n所以 nums 中总共合法分割方案受为 2 。\n</pre>\n\n<p><strong>示例 2: </strong></p>\n\n<pre>\n<b>输入:</b>nums = [2,3,1,0]\n<b>输出:</b>2\n<b>解释:</b>\n总共有 2 种 nums 的合法分割:\n- 在下标 1 处分割 nums 。那么第一部分为 [2,3] ,和为 5 。第二部分为 [1,0] ,和为 1 。因为 5 >= 1 ,所以 i = 1 是一个合法的分割。\n- 在下标 2 处分割 nums 。那么第一部分为 [2,3,1] ,和为 6 。第二部分为 [0] ,和为 0 。因为 6 >= 0 ,所以 i = 2 是一个合法的分割。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n" ,
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o f - b o u n d s < \ \ / c o d e > \ \ u 5 4 8 c < c o d e > u s e - a f t e r - f r e e < \ \ / c o d e > \ \ u 9 5 1 9 \ \ u 8 b e f \ \ u 3 0 0 2 < \ \ / p > \ \ r \ \ n \ \ r \ \ n < p > \ \ u 4 e 3 a \ \ u 4 e 8 6 \ \ u 4 f 7 f \ \ u 7 5 2 8 \ \ u 6 5 b 9 \ \ u 4 f b f \ \ u f f 0 c \ \ u 5 9 2 7 \ \ u 9 0 e 8 \ \ u 5 2 0 6 \ \ u 6 8 0 7 \ \ u 5 1 c 6 \ \ u 5 e 9 3 \ \ u 7 6 8 4 \ \ u 5 9 3 4 \ \ u 6 5 8 7 \ \ u 4 e f 6 \ \ u 5 d f 2 \ \ u 7 e c f \ \ u 8 8 a b \ \ u 8 1 e a \ \ u 5 2 a 8 \ \ u 5 b f c \ \ u 5 1 6 5 \ \ u 3 0 0 2 < \ \ / p > \ \ r \ \ n \ \ r \ \ n < p > \ \ u 5 9 8 2 \ \ u 6 0 f 3 \ \ u 4 f 7 f \ \ u 7 5 2 8 \ \ u 5 4 c 8 \ \ u 5 e 0 c \ \ u 8 8 6 8 \ \ u 8 f d 0 \ \ u 7 b 9 7 , \ \ u 6 0 a 8 \ \ u 5 3 e f \ \ u 4 e e 5 \ \ u 4 f 7 f \ \ u 7 5 2 8 < a h r e f = \ \ \ " h t t p s : \ \ / \ \ / t r o y d h a n s o n . g i t h u b . i o \ \ / u t h a s h \ \ / \ \ \ " t a r g e t = \ \ \ " _ b l a n k \ \ \ " > u t h a s h < \ \ / a > \ \ u 3 0 0 2 \ \ \ " u t h a s h . h \ \ \ " \ \ u 5 d f 2 \ \ u 7 e c f \ \ u 9 e d 8 \ \ u 8 b a 4 \ \ u 8 8 a b \ \ u 5 b f c \ \ u 5 1 6 5 \ \ u 3 0 0 2 \ \ u 8 b f 7 \ \ u 7 7 0 b \ \ u 5 9 8 2 \ \ u 4 e 0 b \ \ u 7 9 3 a \ \ u 4 f 8 b : < \ \ / p > \ \ r \ \ n \ \ r \ \ n < p > < b > 1 . \ \ u 5 f 8 0 \ \ u 5 4 c 8 \ \ u 5 e 0 c \ \ u 8 8 6 8 \ \ u 4 e 2 d \ \ u 6 d f b \ \ u 5 2 a 0 \ \ u 4 e 0 0 \ \ u 4 e 2 a \ \ u 5 b f 9 \ \ u 8 c 6 1 \ \ u f f 1 a < \ \ / b > \ \ r \ \ n < p r e > \ \ r \ \ n s t r u c t h a s h _ e n t r y { \ \ r \ \ n i n t i d ; \ \ / * w e ' l l u s e t h i s f i e l d a s t h e k e y * \ \ / \ \ r \ \ n c h a r n a m e [ 1 0 ] ; \ \ r \ \ n U T _ h a s h _ h a n d l e h h ; \ \ / * m a k e s t h i s s t r u c t u r e h a s h a b l e * \ \ / \ \ r \ \ n } ; \ \ r \ \ n \ \ r \ \ n s t r u c t h a s h _ e n t r y * u s e r s = N U L L ; \ \ r \ \ n \ \ r \ \ n v o i d a d d _ u s e r ( s t r u c t h a s h _ e n t r y * s ) { \ \ r \ \ n H A S H _ A D D _ I N T ( u s e r s , i d , s ) ; \ \ r \ \ n } \ \ r \ \ n < \ \ / p r e > \ \ r \ \ n < \ \ / p > \ \ r \ \ n \ \ r \ \ n < p > < b > 2 . \ \ u 5728 \ \ u 54 c 8 \ \ u 5e0 c \ \ u 8868 \ \ u 4e2 d \ \ u 67e5 \ \ u 627 e \ \ u 4e00 \ \ u 4e2 a \ \ u 5 b f 9 \ \ u 8 c 61 \ \ u f f 1 a < \ \ / b > \ \ r \ \ n < p r e > \ \ r \ \ n s t r u c t h a s h _ e n t r y * f i n d _ u s e r ( i n t u s e r _ i d ) { \ \ r \ \ n s t r u c t h a s h _ e n t r y * s ; \ \ r \ \ n H A S H _ F I N D _ I N T ( u s e r s , & u s e r _ i d , s ) ; \ \ r \ \ n r e
2022-05-22 11:21:15 +08:00
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