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leetcode-problemset/leetcode-cn/problem (Chinese)/奇数和偶数交易 [odd-and-even-transactions].html

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2024-08-06 08:46:50 +08:00
<p>表:<code>transactions</code></p>
<pre>
+------------------+------+
| Column Name | Type |
+------------------+------+
| transaction_id | int |
| amount | int |
| transaction_date | date |
+------------------+------+
transactions_id 列唯一标识了表中的每一行。
这张表的每一行包含交易 id金额总和和交易日期。
</pre>
<p>编写一个解决方案来查找每天 <strong>奇数</strong> 交易金额和 <strong>偶数</strong> 交易金额的 <strong>总和</strong>。如果某天没有奇数或偶数交易,显示为&nbsp;<code>0</code></p>
<p>返回结果表以&nbsp;<code>transaction_date</code> <strong>升序</strong>&nbsp;排序。</p>
<p>结果格式如下所示。</p>
<p>&nbsp;</p>
<p><strong class="example">示例:</strong></p>
<div class="example-block">
<p><b>输入:</b></p>
<p><code>transactions</code> 表:</p>
<pre class="example-io">
+----------------+--------+------------------+
| transaction_id | amount | transaction_date |
+----------------+--------+------------------+
| 1 | 150 | 2024-07-01 |
| 2 | 200 | 2024-07-01 |
| 3 | 75 | 2024-07-01 |
| 4 | 300 | 2024-07-02 |
| 5 | 50 | 2024-07-02 |
| 6 | 120 | 2024-07-03 |
+----------------+--------+------------------+
</pre>
<p><strong>输出:</strong></p>
<pre class="example-io">
+------------------+---------+----------+
| transaction_date | odd_sum | even_sum |
+------------------+---------+----------+
| 2024-07-01 | 75 | 350 |
| 2024-07-02 | 0 | 350 |
| 2024-07-03 | 0 | 120 |
+------------------+---------+----------+
</pre>
<p><strong>解释:</strong></p>
<ul>
<li>对于交易日期:
<ul>
<li>2024-07-01:
<ul>
<li>奇数交易金额总和75</li>
<li>偶数交易金额总和150 + 200 = 350</li>
</ul>
</li>
<li>2024-07-02:
<ul>
<li>奇数交易金额总和0</li>
<li>偶数交易金额总和300 + 50 = 350</li>
</ul>
</li>
<li>2024-07-03:
<ul>
<li>奇数交易金额总和0</li>
<li>偶数交易金额总和120</li>
</ul>
</li>
</ul>
</li>
</ul>
<p><b>注意:</b>输出表以&nbsp;<code>transaction_date</code>&nbsp;升序排序。</p>
</div>